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3 years ago

Collins is working.......

Mathematics

1 answer:

lesya [120]3 years ago

4 0

Let n represent the amount Colin earned on Sunday.

On Sat. he earned n/2; on Sun. he earned n; and on Friday he earned (1/2)(n/2).

Then n/2 + n + n/4 = $70

Mult. all terms by 4 to eliminate fractions:

2n + 4n + n = $280

7n = $280 => n = $40

Colin earned n/2, or $20, on Saturday; n, or $40, on Sunday; and n/4, or $10, on Friday.

Note that $20 and $40 and $10 add up to $70, as they must.

You might be interested in

An even integer can be represented by the expression 2n, where n is any integer. Find three consecutive even integers that have

Setler79 [48]

As consecutive odd numbers differ by two (example: 3, 5, 7), the first odd number can be expressed as 2n + 1, the next can be found by adding two to the first to get 2n + 1 + 2 which simplifies to 2n + 3. Finally the expression for the third consecutive odd integer can be found by adding two to the previous, 2n + 3, to get 2n + 5. Adding these three together and setting them equal to your sum gets the equation

2n + 1 + 2n + 3 + 2n + 5 = 63

Combine like terms and solve For n.

Once you have n, you must substitute it back into your three expressions (2n + 1, 2n + 3, 2n + 5) to find the three odd integers.

Hope this helps :)

7 0

3 years ago

I need help on question 2 i need the simplified answer and the restrictions

Anastaziya [24]

Answer:

x cannot be 5 or -3.

$\frac{x+5}{x+3}$

Step-by-step explanation:

The restrictions for a fraction is that the bottom cannot be 0.

So if we find when the bottom is 0 we have found the values that x cannot be.

Let's solve x^2-2x-15=0.

Since the coefficient of x^2 is 1 all we have to do is find two numbers whose product is -15 and whose sum is -2.

Those numbers are -5 and 3 since (-5)(3)=-15 and (-5)+(3)=-2.

So the factored form of the equation is:

(x-5)(x+3)=0

This means either x-5=0 or x+3=0.

We do have to solve both.

x-5=0 can be solved by adding 5 on both sides.

x-5+5=0+5

x+0=0+5

x=5

x+3=0 can be solved by subtracting 3 on both sides.

x+3-3=0-3

x+0=0-3

x=-3

So x can be any number except x=5 or x=-3.

We already factored the bottom as (x-5)(x+3).

The top is a difference of squares, x^2-a^2,

which can be factored as (x-a)(x+a).

So the top factors as (x-5)(x+5).

The fraction can then be written as:

$\frac{x^2-25}{x^2-2x-15}=\frac{(x-5)(x+5)}{(x-5)(x+3)}$

This can further simplified assuming x is not 5 we can write it as $\frac{x+5}{x+3}$ . I canceled the common factor of (x-5).

5 0

3 years ago

7 + (-5) =______ pls help

Nata [24]

the answer would be 2

8 0

3 years ago

Read 2 more answers

Please help me with this question

Tema [17]

............................

8 0

3 years ago

write the equation of a line in slope intercept form that is parallel to the line x+5y=10 and goes through the point (-5,6)

lilavasa [31]

Answer:

The equation would be y = -1/5x + 5

Step-by-step explanation:

To find the equation of this new line, we first need to identify the slope of the first line. We do this by putting it into slope intercept form.

x + 5y = 10

5y = -x + 10

y = -1/5x + 2

In slope-intercept form, the slope is always the coefficient of x. This makes the slope of the first equation -1/5. Since parallel lines have the same slope, our new slope will also be -1/5.

Given that and the point, we can solve for the equation using point-slope form.

y - y1 = m(x - x1)

y - 6 = -1/5(x + 5)

y - 6 = -1/5x - 1

y = -1/5x + 5

4 0

3 years ago