Question

Roses sell for $3 each and carnations for$1.50 each. If a mixed bouquet of 20 flowers consisting of roses and carnations cost $39 how many of each type of flower is in the bouquet?

Answer 1

3x + 1.50y = 39

12 Roses     2 Carnations

3(12) + 1.50(2) = 39
36 + 3 = 39
39=39

Answer 2

$x-number\ od\ roses\\20-x-number\ of\ carnations\\\\3x+1.5(20-x)=39\\3x+30-1.5x=39\\1.5x=39-30\\1.5x=9\ \ \ \ \ |:1.5\\x=6\\\\20-6=14\\\\There\ was\ 6\ roses\ and\ 14\ carnations.$