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AleksandrR [38]
3 years ago
6

Solve -7 + p = 3 for p. (A) 4 (B) -4 (C) 10 (D) -10

Mathematics
2 answers:
MakcuM [25]3 years ago
3 0
Step 1: Simplify both sides of the equation.

p−7=3

Step 2: Add 7 to both sides.

p−7+7=3+7

p=10

valina [46]3 years ago
3 0
The answer is 10 because you want to add 7 to 3 to get p by itself and it will give you p=10
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A shirt that normally sells for $28.00 before discount was priced at $22.95 after discount what is the percent saved?
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4 0
3 years ago
What’s the distance between polar coordinates (3,−60°)and(−5,105°) ?
Ilya [14]

Answer:

2 Units

Step-by-step explanation:

THere may be easier ways to do it, but I would just convert them to rectangular and find the distance between those.

(3, -60) becomes (3cos(-60), 3sin(-60)) = (3/2, -3*sqrt(3)/2)

(-5, 105) becomes (-5cos(105), -5sin(105)) = (5/2, -5sqrt(3)/2)

Now just use the distance formula, or in other words think of the two points as being connected by a horizontal and vertical line to form a right triangle.  The idea is to find the hypotenuse of that right triangle.

sqrt((3/2 - 5/2)^2 + (-3sqrt(3)/2 + 5sqrt(3)/2)^2)

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sqrt(1 + 3)

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2

6 0
4 years ago
Factor the polynomial.<br><br> −4y²+3xy−12y+9x
Andreyy89
-y(4y-3x)-3(4y-3x)

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4 0
3 years ago
Given: Triangle ABC : triangle ADB. AB =24, AD =16 <br> Find: AC
RoseWind [281]

Answer:

<h2>AC = 36.01</h2>

Step-by-step explanation:

Given ΔABC and ΔADB, since both triangles are right angled triangles then the following are true.

From ΔADB, AB² = AD²+BD²

Given AB = 24 and AD = 16

BD² = AB² - AD²

BD² = 24²-16²

BD² = 576-256

BD² = 320

BD = \sqrt{320}

BD = 17.9

from ΔABC, AC² = AB²+BC²

SInce AC = AD+DC and BC² = BD² + DC² (from ΔBDC )we will have;

(AD+DC)² = AB²+ (BD² + DC²)

Given AD = 16, AB = 24 and BD = 17.9, on substituting

(16+DC)² = 24²+17.9²+ DC²

256+32DC+DC² =  24²+17.9²+ DC²

256+32DC = 24²+17.9²

32DC = 24²+17.9² - 256

32DC = 640.41

DC = \frac{640.41}{32}

DC = 20.01

Remember that AC = AD+DC

AC = 16+20.01

AC = 36.01

6 0
3 years ago
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