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andrew11 [14]
3 years ago
12

The equation x2+3px+p=0, where p is non-zero constant, has equal roots. Find the value of p

Mathematics
1 answer:
Reptile [31]3 years ago
3 0

A quadratic equation has equal roots if and only if the discriminant

\Delta = b^2-4ac

is zero.

So, we have to impose

(3p)^2-4p=0 \iff 9p^2-4p=0 \iff p(9p-4)=0 \iff p=0 \lor\; p=\dfrac{4}{9}

Since p is non-zero, the only possible value for p is 4/9.

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Find the sum for each and present - 66 + 42​
Fed [463]

-24

-66+42

=-24 since it is negative

3 0
3 years ago
Read 2 more answers
-onsider x + 4 = x + 8. What values could be substituted for x to make this a true
devlian [24]

Answer:

No because upon subtracting x on both sides you obtain a false equation of 4=8.

The problem:

What are x values that satisfy:

x+4=x+8?

Step-by-step explanation:

No number can be substituted into x+4=x+8 to make it true.

There is no number that you can find such that when you add 4 to it will give you the same as adding 8 to it.

Also if you subtract x on both sides you obtain the equation 4=8.

4=8 is not true so x+4=x+8 is never true for any x.

7 0
3 years ago
In ∆ABC, point D is the centroid. If (AE) ̅=15, (BF) ̅=27, and (CD) ̅=8, find the following lengths
Anna71 [15]

Answer:

5,18,12 cms are the answer.

Step-by-step explanation:

Given is a triangle ABC.  Point D is the centroid.  

E,F and G are midpoints of CB, BA and AC respectively.

AE, BF and CG are medians of the triangle.

We know that centroid divides the median in the ratio 2:1

Using this we find that AD:DE = 2:1

Or AD+DE:DE = (2+1):1

AE:DE =3:1

15:DE = 3:1 . Hence DE =5 cm.

On the similar grounds we find that DF = 1/3 BF = 9

Hence BD = DF-BF = 27-9 =18 cm

and also

CG = 3/2 times CD = 12 cm.

7 0
3 years ago
Why do some absolute value equations have no solution?
DerKrebs [107]
Because both positive and negative values have<span> a positive </span>absolute value.
6 0
3 years ago
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Which number line shows the correct placement of 20%, 1/3, and 2/3?
BigorU [14]

Answer with Step-by-step explanation:

We are given that

20%

When we change percent into fraction we will divide the percent by 100

\frac{20}{100}=\frac{1}{5}

\frac{1}{3}

\frac{2}{3}

We have to find the line which shows the correct placement of given numbers.

Lcm(3,5)=15

\frac{1\times 3}{5\times 3}=\frac{3}{15}

\frac{1\times 5}{3\times 5}=\frac{5}{15}

\frac{2\times 5}{3\times 5}=\frac{10}{15}

7 0
3 years ago
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