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andrew11 [14]
3 years ago
12

The equation x2+3px+p=0, where p is non-zero constant, has equal roots. Find the value of p

Mathematics
1 answer:
Reptile [31]3 years ago
3 0

A quadratic equation has equal roots if and only if the discriminant

\Delta = b^2-4ac

is zero.

So, we have to impose

(3p)^2-4p=0 \iff 9p^2-4p=0 \iff p(9p-4)=0 \iff p=0 \lor\; p=\dfrac{4}{9}

Since p is non-zero, the only possible value for p is 4/9.

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Solution:

<u>We know that:</u>

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