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2 years ago

Francine uses \dfrac23

Mathematics

1 answer:

andrew11 [14]2 years ago

6 0

Answer:

Step-by-step explanation:

If Francine uses 1/3 cup of pineapple juice for every 1/2 cup of orange juice to make a smoothie then:

1/3 cup of pineapple = 1/2cup of juice

We need to know the amount he will use for 1 cup of Orange juice, say;

x cup of pineapple = 1cup of Orange juice

Equating both

1/3 cup of pineapple = 1/2cup of juice

x cup of pineapple = 1cup of Orange juice

Cross multiply

1/2 × x = 1/3 × 1

x/2 = 1/3

3x = 2

x = 2/3

Hence he will need 2/3 cups of pineapple for 1 cup of Orange juice

You might be interested in

Is 7/9 a rational number ?

zzz [600]

Answer:

Yes.

Step-by-step explanation:

Rational numbers can be represented as fractions with integers. The denominator must not equal 0.

$\frac{7}{9}$ is already in this form. This means that it's a rational number.

Hope this helps.

8 0

2 years ago

WILL GET BRAINLY the equation has and . a valid solution for x is

Julli [10]

Answer:

Is there supposed to be a attachment. because I dont see anything

Step-by-step explanation:

7 0

2 years ago

if 16 friends went on a trip and it was 200 miles away how many miles would it take to split the trip into 16 parts?

dalvyx [7]

12.8 miles would take the 16 friends to split the trip into 16 parts

8 0

2 years ago

A cone has a diameter of 3 inches the cone holds 12 cubic inches of water to the nearest in what is the height

LUCKY_DIMON [66]

Answer:

5 inches

Step-by-step explanation:

A cone's volume can be found using the formula $V = \frac{1}{3} \pi r^2 h$ . If the cone has a diameter of 3 inches then its radius is half r= 1.5 inches. Substitute r = 1.5 and V = 12 cubic inches.

$V = \frac{1}{3} \pi r^2 h \\12 = \frac{1}{3} \pi (1.5)^2 h \\12 = \frac{1}{3} \pi (2.25) h\\12 = 2.355h\\5.10 = h$

This means the height of the cone is 5.10 inches or to the nearest inch 5 inches.

3 0

3 years ago

If lim x-> infinity ((x^2)/(x+1)-ax-b)=0 find the value of a and b

MAXImum [283]

We have

$\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}$

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0$

The rational term vanishes as x gets arbitrarily large, so we can ignore that term, leaving us with

$\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0$

and this happens if a = 1 and b = -1.

To confirm, we have

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-x+1\right)=\lim_{x\to\infty}\frac{x^2-(x-1)(x+1)}{x+1}=\lim_{x\to\infty}\frac1{x+1}=0$

as required.

3 0

2 years ago