Answer: the answer is attached
Step-by-step explanation:
2y/y-3. 4y-12/2y+6
4. It cannot be a constant or unit rate relationship because the value of k = y/x vary across table values.
5. The relationship in Tuesday's table can be described by a constant unit rate.
<h3>What is a Constant Unit rate Relationship?</h3>
A constant unit rate relationship can be described as a relationship between two input and output variables, x and y, in such a way that, k = y/x. "k" is the constant of proportionality of the relationship or the unit rate between the two variables.
4. We have the following:
5/20 = 1/4
10/40 = 1/4
12/60 = 1/5
14/80 = 7/40
16/100 = 4/25
Thus, this cannot be a constant or unit rate relationship because the value of k = y/x vary across table values.
5. 4/20 = 1/5
8/40 = 1/5
12/60 = 1/5
16/80 = 1/5
20/100 = 1/5
Thus, the value of k is the same across all table values, therefore, the relationship in Tuesday's table can be described by a constant unit rate.
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Given :
On a number line, suppose the coordinate of A is 0, and AR = 15.
To Find :
the possible coordinates of the midpoint of AR.
Solution :
Their can be two points R which is at a distance of 15 units from the A .
One is -15 and other is 15.
Now, mid-point of A(0) and R(-15) is M (-7/2).
Also, mid-point of A(0) and R(15) is M (7/2).
Therefore, possible coordinates of the midpoint of AR is 7/2 , -7/2.
Hence, this is the required solution.
Answer:
150
Step-by-step explanation:
3×0=0
3×1=3
3×2=6
3×3=9
....
3×50=150
