Answer:
INPUT "What is the amount of rupees you want converted into paisa"; rupees
paisa = rupees*100
PRINT paisa
Explanation:
done in QBASIC
the semicolon in the 1st line makes the question have a ? at the end. the rupees key word in the 1st line saves the input as a variable
then the second line multiplies by 100 since there are 100 paisa in 1 rupee
- Tons of celebrities live in California. You have the kardashians, youtubers and internet stars, musicians, millionaires, etc.
-California is known for gold, silicon, etc.
-Some words that describe California are "economic", "melting pot", "adventurous" "beaches" "Hollywood" "sunny" etc.
Considering the situation described above, the fraction of the CPU execution that is devoted to handling clock interrupts "<u>12 percent</u>."
<h3>CPU Execution process.</h3>
The process of CPU Execution involves the execution of an instruction which in life fetches an instruction from memory through its ALU to carry out an operation and then saves the result to memory.
To illustrate the fraction of the CPU execution that is devoted to handling clock interrupts, we have:
60 × 2 msec = 120 msec ÷ 1 sec = 12 percent.
Hence, in this case, it is concluded that the correct answer is <u>12 percent CPU</u> devoted to the clock.
Learn more about the CPU execution here: brainly.com/question/14400616
No, network traffic management software is only concerned with the health of the Network.
Answer: 0.3042
Explanation:
Let A and B are the events to that job done by Printer I and Printer II respectively.
Given : P(A)=0.40 P(B)=0.60
Printing time of Printer I is Exponential with the mean of 2 minutes.
i.e. average number of job done in one minute:
The cumulative distribution function (CDF) for exponential distribution:-
, where
is the mean.
Then, the cumulative distribution function (CDF) for Printer I:-

i.e. 
Printing time of Printer II is Uniform between 0 minutes and 5 minutes.
The cumulative distribution function (CDF) for uniform distribution in interval (a,b) :-

Then, 
i.e. 
Now, the required probability :-

Hence, the required probability = 0.3042