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Anestetic [448]
3 years ago
5

How would you solve k^2-5k+6=0

Mathematics
2 answers:
mariarad [96]3 years ago
6 0
K^2-5k+6=0
k^2-5k=-6
k-2.23k=2.44
1.23k=2.44
k=1.99
Usimov [2.4K]3 years ago
4 0
<span>
 k2 + -5k + 6 = 0  

</span> 6 + -5k + k2 = 0
<span>
 6 + -5k + k2 = 0  

</span><span>Solving for variable 'k'.   
</span>
Factor a trinomial. (2 + -1k)(3 + -1k) = 0 2 + -1k = 0 <span>k = {2, 3}</span>

hoped this helped i skipped some steps so you don't have to wait
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