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Anestetic [448]
3 years ago
5

How would you solve k^2-5k+6=0

Mathematics
2 answers:
mariarad [96]3 years ago
6 0
K^2-5k+6=0
k^2-5k=-6
k-2.23k=2.44
1.23k=2.44
k=1.99
Usimov [2.4K]3 years ago
4 0
<span>
 k2 + -5k + 6 = 0  

</span> 6 + -5k + k2 = 0
<span>
 6 + -5k + k2 = 0  

</span><span>Solving for variable 'k'.   
</span>
Factor a trinomial. (2 + -1k)(3 + -1k) = 0 2 + -1k = 0 <span>k = {2, 3}</span>

hoped this helped i skipped some steps so you don't have to wait
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A quadrilateral has angles that measure 101°, 133°, and 76°. what is the measure of the fourth angle?
Mars2501 [29]

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3 years ago
Making coconut cookies. The recipe calls for 420 g of coconut and 120 g of sugar. Only has 252 g of coconut. How much sugar must
geniusboy [140]

Answer: 72 grams.

Step-by-step explanation:

Let be "s" the amount of sugar in grams that  must be used for 252 grams of coconut to keep the same ratio of coconut to sugar.

Knowing that in the recipe for the coconut cookies, should be 420 grams of coconut and 120 grams of sugar, and you only have 252 grams of coconut, you can set up this proportion to find "s":

\frac{420grams}{120grams}=\frac{252grams}{s}

Now, you need to solve for "s":

\frac{420grams}{120grams}=\frac{252grams}{s}\\\\s(\frac{420grams}{120grams})=252grams\\\\s=(252grams)(\frac{120grams}{420grams})\\\\s=72grams

4 0
3 years ago
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sergejj [24]
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Read 2 more answers
I need help I'm struggling at this can someone give me the answers
Shkiper50 [21]
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3 years ago
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