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3 years ago

How would you solve k^2-5k+6=0

Mathematics

2 answers:

mariarad [96]3 years ago

6 0

K^2-5k+6=0
k^2-5k=-6
k-2.23k=2.44
1.23k=2.44
k=1.99

Usimov [2.4K]3 years ago

4 0

<span>
k2 + -5k + 6 = 0

</span> 6 + -5k + k2 = 0
<span>
6 + -5k + k2 = 0

</span><span>Solving for variable 'k'.
</span>
Factor a trinomial. (2 + -1k)(3 + -1k) = 0 2 + -1k = 0 <span>k = {2, 3}</span>

hoped this helped i skipped some steps so you don't have to wait

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Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p

zubka84 [21]

Answer: The required answers are

(a) 0.25, (b) 0.62, (c) 6.

Step-by-step explanation: Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

$P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.$

(a) The probability of getting 5 heads is given by

$P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.$

(b) The probability of getting 5 or more than 5 heads is

$P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.$

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

$P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.$

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

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3 years ago

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Rom4ik [11]

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<h3>What is a data table?</h3>

A table is an arrangement of information or data, typically in rows and columns, or possibly in a more complex structure. Tables are widely used in communication, research, and data analysis.

The data table for the given data is given below:

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2 years ago

What is m when 3m + 5 = 8

iren [92.7K]

Answer:

Step-by-step explanation:

If 3m + 5 = 8

We can say 8 - 5 = 3m

So, 3 = 3m

So, m = 1.

1 x 3 = 3!

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3 years ago

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The median of the following data will ________________________ when you in add a data value of 1? (DO MATH on paper!) 8, 9, 9, 4

svlad2 [7]

Answer:

B decrease

Step-by-step explanation:

First, lets put the numbers in order from greatest to least.

10 9 9 8 6 4 4

Second, let's find the median without number 1. (The median is in bold.)

10 9 9 8 6 4 4

Third, let's add the number 1.

10 9 9 8 6 4 4 1

Fourth, let's find the median with the number 1.

10 9 9 8 6 4 4 1

Since there are two numbers in the middle let's find the average between them.

8+6=14

14/2= 7

Last, let's compare the two medians.

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3 years ago

HELP PLEASE !?!? I suck at math

Anna35 [415]

To graph the equation, plot a few points then connect then with a line.

f(x) = 440 - 55x

Plug in numbers for x to get the y value.

f(0) = 440
f(1) = 385
f(2) = 330
f(3) = 275
f(4) = 220
f(5) = 165

So when you graph these points, the y intercept is y = 440 because the graph crosses the y axis at (0, 440).

The x intercept is where the graph crosses the x axis. This happens when y = 0.

0 = 440 - 55x. Solve for x.

55x = 440
x = 8

So the x intercept is x = 8

7 0

3 years ago