100+6=106% = 1.06
55x1.06^10= 98.50
98.50 + 20(10) = 258.50
$258.50
42x + 4 = 130
42x = 130-4
42x = 126
x = 3
The degree of freedom for t statistic is 11.
According to the given question.
For a repeated-measure study, comparing two treatments with 12 scores in each treatment .
So, we can say that sample size, n = 12.
We know that, when you have a sample and estimate the mean, we have
n – 1 degrees of freedom, where n is the sample size.
Therefore,
The degree of freedom for the given sample test will be
d.f = n -1
⇒ d.f = 12 - 1
⇒ d.f = 11
Hence, the degree of freedom for t statistic is 11.
Find out more informaion about degree of freedom for sample test here:
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Answer:
-288
Step-by-step explanation:
<h3>Given AP</h3>
<u>To find,</u>
- The sum of first 18 terms
<h3>Solution</h3>
<u>The first and 18th terms as per the formula</u>
- t(1) = 3 - 2 = 1
- t(18) = 3 - 18*2 = 3 - 36 = -33
- S18 = 1/2*18(1 - 33) = 9*(-32) = -288
<u>Answer is</u> -288
Answer:
Out of 450 phones 18 of them will have a defect.
Step-by-step explanation:
As we know that out of 75 phones 3 of them will have a defect, this means that we are able to calculate how many defects there will be from 450 phones. You can do this by first dividing 450 by 75, this gives you 6. This means that 75 will go into 450 6 times.
From this we are able to work out the number that will have defects. This is because we know that 75 goes into 450 6 times and that for each 75 phones there will be 3 defects. So to work out the number of phones out of 450 that would be defects you would simply multiply 3 by 6, this gives you 18. This shows that out of 450 phones 18 of them will have a defect.
1) Divide 450 by 75.

2) Multiply 6 by 3.