Find the zeros of the function f(x)=x^3-7x^2+6x

Mathematics

1 answer:

grandymaker [24]3 years ago

3 0

f(x)=x^3-7x^2+6x

The zeros of the function

x^3-7x^2+6x = 0

x(x^2 -7x +6) = 0

x(x - 6)(x - 1) = 0

x = 0

x - 6 = 0; x = 6

x - 1 = 0; x = 1

Answer

x = 0, 1 , 6

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