Which decimal equal to six-tenhths? 0.6 0.15 0.2 0.3 0.4

2. Every December, Tagaytay City Science National High School is sponsoring a

kirza4 [7]

Answer:

a: 162

b: 142

Step-by-step explanation:

a: december 1=2

a: december 2=6

a: december 3 = 6 x 3 = 18

a: december 4 = 18 x 3 =54

a: december 5 = 54 x 3 =162

~ triples the number of newspapers means "x3" ~

so on the last day, 162 newspapers

B: sum up all the newspapers:

2 + 6 + 18 + 54 + 162

= 8 + 18 + 54 + 162

= 26 + 54 + 162

= 80 + 162

= 242 all in total newspapers

3 0

2 years ago

Find the first derivative?

professor190 [17]

You could do the question the way it is written, but it is far easier to bring the negative power up to the numerator.

y= x^2 - 3. The derivative of that is
dy/dx = 2x The three is a constant and is always dropped when a derivative is taken
d(-3)/dx = 0

If you are a purist and want to solve the question the way it is written, you could do it this way.

dy/dx = d(1)/dx x^-2 - d(x^-2)/dx * 1
======================
(x^-2)^2

dy/dx = - (-2 x^ - 3) / x^-4

dy/dx = 2 x^-3 * x^4
dy/dx = 2 x^(-3 + 4)
dy/dx = 2x ^ 1
dy/dx = 2x <<<<< answer

8 0

3 years ago

the lowest temperature ever recorded on earth's surface was −128.5°f. the highest temperature was 262.5°f higher than the lowest

vlabodo [156]

Answer: 134 °f

Step-by-step explanation:

Lowest is -128.5 °f, the highest is 262.5 °f higher than the lowest.

you would simply add 262.5 °f to your -128.5 °f, giving you 134 °f.

another way of doing this is subtracting 128.5 from 262.6

5 0

3 years ago

Read 2 more answers

the production of a printer consists of the cost of raw material at 100 dollars the cost of overheads at 80$ and wages at 120$ i

Vadim26 [7]

Answer:

The percentage increase in the production cost of the printer is 3%.

Step-by-step explanation:

We are given that the production of a printer consists of the cost of raw material at 100 dollars the cost of overheads at 80$ and wages at 120$.

Also, the cost of raw materials and overheads are increased by 11% and 20% respectively while wages are decreased by 15%.

Cost of raw material = $100

Cost of overheads = $80

Cost of wages = $120

So, the total cost of the printer = $100 + $80 + $120

= $300

Now, the increase in the cost of raw material = $100 + 11% of $100

= $\$100 + (\frac{11}{100} \times \$100)$

= $100 + $11 = $111

The increase in the cost of overheads = $80 + 20% of $80

= $\$80 + (\frac{20}{100} \times \$80)$

= $80 + $16 = $96

The decrease in the cost of wages = $120 - 15% of $120

= $\$120 - (\frac{15}{100} \times \$120)$

= $120 - $18 = $102

So, the new cost of a printer = $111 + $96 + $102 = $309

Now, the percentage increase in the production cost of the printer is given by;

% increase = $\frac{\text{Net increase in the cost of printer}}{\text{Original cost of printer}} \times 100$

= $\frac{\$309- \$300}{\$300} \times 100$

= 3%

Hence, the percentage increase in the production cost of the printer is 3%.

4 0

3 years ago

The data sets show the years of the coins in two collections. Derek's collection: 1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910

KATRIN_1 [288]

Answer:

Derek's collection :

Mean= 1929

Median= 1930

Range= 54

IQR = 48

MAD= 23.75

Paul's collection:

Mean= 1929

Median= 1929.5

Range= 15

IQR = 6

MAD= 3.5

Step-by-step explanation:

1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910

Mean is given by:

(1950+1952+ 1908+1902+1955+1954+1901+1910)/8

=1929

absolute deviation from mean is:

|1950-1929|= 21

|1952-1929|= 23

|1908-1929|= 21

|1902-1929|= 27

|1955-1929|= 26

|1954-1929|= 25

|1901-1929|= 28

|1910-1929|= 19

from the mean of absolute deviation gives the MAD of the data i.e.

(21+23+21+27+26+25+28+`9)/8

23.75

:arrange the given data to get the range and median

1901 1902 1908 1910 1950 1952 1954 1955

The minimum value is: 1901

Maximum value is: 1955

Range is: Maximum value-minimum value

Range=1955-1901

Range= 54

median is (1910+1950)/2

1930

the lower set of data=

1901 1902 1908 1910

first quartile becomes

1902+1908)/2

Q1=1905

and upper set of data is:

1950 1952 1954 1955

we find the median of the upper quartile or third quartile is:

1952+1954)/2=1953

Q3-Q1=1953-1905=

IQR=48

Paul's collection:

1929, 1935, 1928, 1930, 1925, 1932, 1933, 1920

Mean is given by:

1929+1935+ 1928+ 1930+ 1925+ 1932+1933+1920)/8

1929

absolute deviation from mean is:

|1929-1929|=0

|1935-1929|= 6

|1928-1929|= 1

|1930-1929|= 1

|1925-1929|= 4

|1932-1929|= 3

|1933-1929|= 4

|1920-1929|= 9

Hence, we get:

MAD=0+6+1+1+4+3+4+9/8

28/8

3.5

arrange the data in ascending order we get:

1920 1925 1928 1929 1930 1932 1933 1935

Minimum value= 1920

Maximum value= 1935

Range= 15 ( 1935-1920=15 )

The median is between 1929 and 1930

Hence, Median= 1929.5

Also, lower set of data is:

1920 1925 1928 1929

the first quartile or upper quartile is

1925+1928/2

1926.5

and the upper set of data is:

1930 1932 1933 1935

We have

1932+1933)/2

1932.5

IQR is calculated as:

Q3-Q1

6

7 0

3 years ago