Answer:
A) -4
B) 4 units apart
C) no values of x
Step-by-step explanation:
1) slope of m: (3-2)/(10-8) = ½
m(x) = ½x + c
2 = ½(8) + c
c = -2
m(x) = ½x - 2
m(16) = 6
h(4) = (4-2)²/2 = 4/2 = 2
h(4)-m(16) = 2-6 = -4
B) y-intercept of:
*h(x) = ½(0-2)² = 2
*m(x) = -2
from the equation found before
2 - (-2) = 4 units apart
C) m(x) = (x-4)/2
m(x) > h(x)
(x-4)/2 > ½(x-2)²
x-4 > x²-4x+4
x²-5x+8 < 0
(x - 2.5)² + 1.75 < 0
Never negative
<u>Given</u>:
The quadratic equation is 
We need to determine the solutions of the quadratic equation.
<u>Solution</u>:
Let us solve the equation to determine the value of x.
Adding both sides of the equation by 5x and 3, we get;
The solution of the equation can be determined using quadratic formula.
Thus, we get;
Thus, the two roots of the equation are 
and 
Hence, the solutions of the equation are and
The required solution is ∠RQT = 202° and ∠QTS = 51°
<h3 />
<h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.
Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.
Now, the given circle has a cyclic quadrilateral QRST in which it is given that ∠RQT = 202° and ∠QRS = 129°
Since,sum of the opposite angles of a cyclic quadrilateral = 180°
⇒∠QTS + ∠QRS = 180°
⇒ ∠QTS + ∠129° = 180°
⇒ ∠QTS = 180° - ∠129°
⇒ ∠QTS = 51°
Hence,the requires angles are ∠RQT = 202° and ∠QTS = 51°.
More about cyclic quadrilateral :
brainly.com/question/14323008
#SPJ1
The reason you got it wrong is because you solved for the side a instead of the angle Z, which was what the question asked you to solve for. You can find Z by doing cos Z = 12/35, which will get you cos Z = 0.343, and Z will be equal to about 70º.
Answer:
y = 2x-2
Step-by-step explanation:
