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Furkat [3]
3 years ago
13

Solve -4x^2 + 6x - 10 = 0 using the quadratic formula. Show each step.

Mathematics
1 answer:
Musya8 [376]3 years ago
5 0
-12x-10=0 since the X can't combine with non X numbers
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Divide it by 24 then that answer is divided by 60 to get 132.7777 which you can have so 133 people per minute
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Determine if the following scenario is inductive or deductive reasoning:
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A grocery store has 120 bottles of spring
notka56 [123]

Question:

A grocery store has 120 bottles of spring water in stock.  The store orders bottles of spring water in cases of 24.  The store wants to order enough cases of spring water so it has more than 500 bottles in stock.  Which inequality best models this situation?

A.  24x + 120 > 500

B.  24x - 120 > 500

C.  24x + 500 > 120

D.  24(x+120) > 500

Answer:

Option  A.  24x + 120 > 500  is the inequality that best models this situation.

Step-by-step explanation:

The Number of bottles of spring  water in the stock = 120

Each case of the spring water bottles contains 24 bottles

The store wants  to order enough cases of spring water so  that it has over 500 bottles in stock.

So there are already 120 bottles in stock .

The store will order

24x +120  > 500

where x  is the number of spring water bottle cases

5 0
3 years ago
Suppose a manufacturer finds that 95% of their production is normal but the final 5% has one or more flaws. Each flawed good has
RUDIKE [14]

Answer:

1)    

FLAW                         TYPE2         NO TYPE2 FLAW

TYPE1                         0.015           0.025

NO TYPE1 FLAW        0.01             0.95

2) 0.04 and $0.04

3) 0.025 and $0.025

4) 0.015 and $0.015

5) 0.95 and $0.95

Step-by-step explanation:

Given that;

financial cost = $1

p(flaw) = 0.05  

p(type 1 flaw / flaw) = 80% = 0.8

p(type 2 flaw / flaw) = 50% = 0.5

p( type 1 and 2 flaw/flaw) = 30% = 0.30

1) Bivariate Table

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw)  = 0.05 × 0.5 = 0.025

p( type 1 and 2 flaw) =  p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

p( only 1 flow) = 0.04 - 0.015 = 0.025

p( only 2 flow) =  0.025 - 0.015 = 0.01

THEREFORE  the Bivariate Table;

FLAW                         TYPE2         NO TYPE2 FLAW

TYPE1                         0.015           0.025

NO TYPE1 FLAW       0.01              0.95

2) probability and expectations of type 1 flaw?

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

Expected financial cost to the firm per good = $1 × 0.04 = $0.04

3)  probability and expectation of Type 2 flaw

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw)  = 0.05 × 0.5 = 0.025

Expected financial cost to the firm per good = $1 × 0.025 = $0.025

4) probability and expectations of Type 1 and 2 flaws

p( type 1 and 2 flaw) =  p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

Expected financial cost to the firm per good = $1 * 0.015 = $0.015

5) probability and expectations of no flaws?

Probability of no flaw = P(No flaw) =95% =  0.95

Expected financial cost saved the firm per good due to no flaw

= $1 × 0.95 = $0.95

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3 years ago
If Frida has five friends who are available available to go to the movies with her but she only has four extra tickets how many
Fynjy0 [20]

Answer:

Step-by-step explanation: she only has 3 because of herself

3 0
3 years ago
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