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Komok [63]
2 years ago
10

QUESTION 3 -- There are two right triangles, Triangle A and Triangle B. In Triangle A, besides the right angle, one more angle i

s given and one side length is given. In Triangle B, besides the right angle, no other angles are given and two sides length are given. In your opinion, which would be the easier problem to start solving? Please explain your reasoning with mathematically relevant details and principles.
Mathematics
1 answer:
Jlenok [28]2 years ago
6 0

Answer:

not b

Step-by-step explanation:

its c because b and a dont make sense

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Can someone help please?
Katyanochek1 [597]

Answer:

(6,9)

Step-by-step explanation:

the x place is counting by 2 and the y place is going up by 3

7 0
3 years ago
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Line AB has endpoints A(3,4) and B(-2,8). What is AB to the nearest tenth
Nadya [2.5K]

Answer:

6.4

Step-by-step explanation:

To find the distance you have to do this formula.

\sqrt{(x2 -x1)^{2}+(y2-y1)^{2}}  \\\sqrt{(-2 -3)^{2} + (8-4)^{2}\\} \\\sqrt{(-5)^{2} + (4)^{2}} \\\sqrt{25 + 16} \\\sqrt{41} \\ \\\sqrt{41} = 6.40312\\6.4

6.4 is the answer rounded to the nearest tenth.

Hope this helps!!

3 0
2 years ago
The expression
mafiozo [28]

Answer:

(2) x2+1+4/x+2

Step-by-step explanation:

I hope i am right sorry if i am wrong.

4 0
3 years ago
What is p=2(e+w)for e solve for indicated variable?
vagabundo [1.1K]
p=2(e+w) \\ p=2e+2w \ \ \ /-2w \\ p-2w=2e \ \ \ /:2 \\ \dfrac{p-2w}{2} =e \\  \dfrac{1}{2} (p-2w)=e \\  \dfrac{1}{2} p - w=e
7 0
3 years ago
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The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given
slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

\tau = 2438.155\,yr

The particular solution of the differential equation is:

m(t) = 10\cdot e^{-\frac{t}{2438.155} }

d) The amount of radium after 300 years is:

m(300) \approx 8.842\,g

4 0
3 years ago
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