All categories

3 years ago

Selina didn't use the distributive property correctly. Where did she go wrong? Explain your thinking.

Mathematics

1 answer:

GarryVolchara [31]3 years ago

6 0

Answer:

PEMDAS

Step-by-step explanation:

Well, I don't know if there should be a picture of the problem that should go with the question. But a trick for solving distributive property is to use the trick PEMDAS In order.

For Example:

P-Paraenthese

E-Exponent

M-Multiply

D-Divide

A-Add

S-Subtract

NOTE!

Remember to always Multiply and divide BEFORE adding and subtracting.

Hoped this helped!

You might be interested in

For a school event, of the athletic field is reserved for the fifth-grade classes.

Rashid [163]

Answer:

1/4

Step-by-step explanation:

4 classes, each class gets one spot!

4 0

3 years ago

Give away 100 B points

SashulF [63]

Answer:

henlo -u-

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

The Confidence interval is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and the critical values are:

$\chi^2_{\alpha/2}=20.09$

$\chi^2_{1- \alpha/2}=1.65$

And replacing into the formula for the interval we got:

$\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0

3 years ago

You scored on a game show is -300 you answer the final question correctly,so you win 400 points.what is your final score

Rasek [7]

Answer:

Your score is 100.

Step-by-step explanation:

If you have -300 and add +300 you will end up with 0 because when a positive and a negative that are equal cancel each other out. So if you add +300 to -300 you get 0 but its 400 so 300 + 100 is 400 so you have +100 left. : )

4 0

2 years ago

Donna is running around a track.It takes her 3 1/2 minutes to run 1/4 of a lap.If she keeps running at the same speed,how long w

meriva

Answer:

70 minutes

Step-by-step explanation:

3 1/2 ÷1/4= 14 ×5= 70

so you first make 3 1/2 to an improper fraction, then you find the greatest common denominator between 7/2 and 1/4 which is 4, so you multiple 7/2 by 2 and get 14/4 and divide that by 1/4 and get 14minutes now multiply that by 5 laps and receive 70 minutes.

6 0

3 years ago

Selina didn't use the distributive property correctly. Where did she go wrong? Explain your thinking.​

Selina didn't use the distributive property correctly. Where did she go wrong? Explain your thinking.