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miskamm [114]
4 years ago
8

Selina didn't use the distributive property correctly. Where did she go wrong? Explain your thinking.​

Mathematics
1 answer:
GarryVolchara [31]4 years ago
6 0

Answer:

PEMDAS

Step-by-step explanation:

Well, I don't know if there should be a picture of the problem that should go with the question. But a trick for solving distributive property is to use the trick PEMDAS In order.

For Example:

P-Paraenthese

E-Exponent

M-Multiply

D-Divide

A-Add

S-Subtract

NOTE!

Remember to always Multiply and divide BEFORE adding and subtracting.

Hoped this helped!

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How do you verify this trigonometric identity? cos^2 θcot^2 θ = cot^2 θ - cos^2 θ
sattari [20]
<h3>Explanation:</h3>

Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).

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8 0
3 years ago
HELPPPP ME PLZZZZ!!!!!!
mihalych1998 [28]
<h3>Answers:</h3>

14.  Each leg is   21\sqrt{2}  units long.

15 (a). The longer leg is 7\sqrt{3}  units long

15 (b). The hypotenuse is 14 units long

=====================================================

Explanations:

For a 45 degree right triangle, aka 45-45-90 triangle, the hypotenuse is equal to sqrt(2) times the short leg. Algebraically we can say

y = x\sqrt{2} where x is the leg and y is the hypotenuse

Let's solve for x

y = x\sqrt{2}\\\\x\sqrt{2} = y\\\\x = \frac{y}{\sqrt{2}}\\\\x = \frac{y\sqrt{2}}{\sqrt{2}*\sqrt{2}} \ \text{rationalizing denominator}\\\\x = \frac{y\sqrt{2}}{2}\\\\

Now plug in the given hypotenuse y = 42, this leads to,

x = \frac{y\sqrt{2}}{2}\\\\x = \frac{42\sqrt{2}}{2}\\\\x = \frac{42}{2}\sqrt{2}\\\\x = 21\sqrt{2}\\\\

---------------------------

For a 30-60-90 triangle, the hypotenuse is double that of the short leg. So the hypotenuse is 2*7 = 14.

The longer leg is equal to sqrt(3) times the short leg. The longer leg is 7\sqrt{3}

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3 years ago
Solve 5m − 3h = 45 for h. Show your work.
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5m − 3h = 45

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4 years ago
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