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sveticcg [70]
3 years ago
7

Who ever gets this correct ill give brainliest and thank you and 5 stars

Mathematics
1 answer:
DIA [1.3K]3 years ago
5 0
1 -15
2 27
3 2010
4 -38
5 376
6 -200
7 -3
8 150
9 41
10 -240
11 120
12 -60
13 1
14 9
15 23
16 107
17 45
18 19
19 0
20 4
21 12
22 0
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s -  \frac{1}{3} =  \frac{4}{9} \\ \\ s =  \frac{4}{9} +  \frac{1}{3} \\ \\ s =  \frac{7}{9} \\ \\ Answer: \fbox {s = 7/9} \ or \ \fbox {s = 0.7778}
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Factor the expression: 84x – 12x
liberstina [14]
Subtract 12x from 84x = 72x
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. A right cylindrical drum is to hold 7.35 cubic feet of liquid. Find the dimensions (radius of the base and height) of the drum
Drupady [299]

Answer:

r=1.05\ \text{ft}

h=2.12\ \text{ft}

20.91\ \text{ft}^3

Step-by-step explanation:

r = Radius

h = Height

Volume of cylinder = 7.35\ \text{ft}^3

V=\pi r^2h\\\Rightarrow h=\dfrac{V}{\pi r^2}\\\Rightarrow h=\dfrac{7.35}{\pi r^2}

Surface area is given by

A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi r^2+2\pi r\dfrac{7.35}{\pi r^2}\\\Rightarrow A=2\pi r^2+\dfrac{14.7}{r}

Differentiating with respect to radius we get

\dfrac{dA}{dr}=4\pi r-\dfrac{14.7}{r^2}

Equating with zero we get

0=4\pi r-\dfrac{14.7}{r^2}\\\Rightarrow 4\pi r=\dfrac{14.7}{r^2}\\\Rightarrow r^3=\dfrac{14.7}{4\pi}\\\Rightarrow r=(\dfrac{14.7}{4\pi})^{\dfrac{1}{3}}\\\Rightarrow r=1.05

\dfrac{d^2A}{dr^2}=4\pi-2\times \dfrac{14.7}{r^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=4\pi+2\times \dfrac{14.7}{1.05^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=37.96>0

So, the value of the function is minimum at r=1.05

h=\dfrac{7.35}{\pi r^2}=\dfrac{7.35}{\pi 1.05^2}\\\Rightarrow h=2.12

So, the radius and height which would minimize the surface area is 1.05 feet and 2.12 feet respectively.

Surface area

A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi \times 1.05^2+2\pi 1.05\times 2.12\\\Rightarrow A=20.91\ \text{ft}^3

The minimum surface area is 20.91\ \text{ft}^3.

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3 years ago
Passes through (1,4) and is parallel to the line y=2x-3
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Answer:

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Answer:

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Step-by-step explanation:

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