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3 years ago

What is 5 with the power of 0

Mathematics

2 answers:

masha68 [24]3 years ago

8 0

$5^{0}$ = 1

When a number has an exponent of 0, the number always becomes/equals 1.

seraphim [82]3 years ago

3 0

Five to the power of two is two fives multiplying together, so zero fives multiplying together is zero.

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In a factory A, about 3 out of every 2,000 toys have a defect. In factory B, about 5 out of every 4,500 toys have a defect. One

gavmur [86]

Answer:

Step-by-step explanation:

Factory A proportion:

3 : 2,000

Factory B proportion:

5 : 4,500 (this can be simplified):

1 : 900

Now plug in 18,000 to each proportion:

Factory A:

x : 18,000

3 : 2,000

x = 27

Factory B:

x : 18,000

1 : 900

x = 20

Factory A had the greater amount of defects, 27

7 0

3 years ago

Find the equation of a line that passes through (0,0) that is perpendicular to 2x+3y=-6

Dovator [93]

The slope-intercept form of a line:

$y=mx+b$

m - slope

b - y-intercept

Convert 2x + 3y = -6 to the slope-intercet form:

$2x+3y=-6$ subtract 2x from both sides

$3y=-2x-6$ divide both sides by 3

$y=-\dfrac{2}{3}x-2$

Let $k:y=m_1x+b_1$ and $l:y=m_2x+b_2$

$l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}$

We have $m_1=-\dfrac{2}{3}$

Therefore

$m_2=-\dfrac{1}{-\frac{2}{3}}=\dfrac{3}{2}$

We have the equation of a line:

$y=\dfrac{3}{2}x+b$

Put the coordinates of the point (0, 0) to the equation:

$0=\dfrac{3}{2}(0)+b$

$0=b\to b=0$

Answer: $\boxed{y=\dfrac{3}{2}x}$

8 0

3 years ago

Which of the following sets of ordered pairs represents a function?

scZoUnD [109]

Answer: your answer is A) & D)

Step-by-step explanation: Hope this helps :)

6 0

2 years ago

Read 2 more answers

Find the indefinite integral. (Use C for the constant of integration.) e2x 25 e4x dx.

Sladkaya [172]

Answer:

The solution is $\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] + C$

Step-by-step explanation:

From the question

The function given is $f(x) = \frac{e^{2x}}{ 25 + e^{4x}} dx$

The indefinite integral is mathematically represented as

$\int\limits {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx$

Now let $e^{2x} = u$

=> $\frac{du}{dx} 2e^{2x}$

=> $2 e^{2x}dx = du$

$\int\limits {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx = \int\limits {\frac{1}{ 2(25 + u^2)} } \, du$

$= \frac{1}{2} \int\limits {\frac{1}{ 25 + u^2)} } \, du$

$= \frac{1}{2} \int\limits {\frac{1}{ 5^2 + u^2)} } \, du$

$= \frac{1}{2} \frac{tan^{-1} [\frac{u}{5} ]}{5} + C$

Now substituting for u

$\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] + C$

3 0

3 years ago

3) When solving a one-step equation, we apply the inverse operation to the value on the _____ of the variable.

sesenic [268]

Answer:

To solve one-step equations, we do the inverse (opposite) of whatever operation is being performed on the variable, so we get the variable by itself. The inverse operations are: Addition and subtraction. Multiplication and division.

Step-by-step explanation:

by it self.

3 0

3 years ago