<em><u>Question:</u></em>
The difference of two numbers is nine if the larger number is one more than twice the smaller number find a larger number
<em><u>Answer:</u></em>
<em><u>The larger number is 17</u></em>
<em><u>Solution:</u></em>
Let the smaller number be "a"
Let the larger number be "b"
The difference of two numbers is nine
Therefore,
b - a = 9 ------ eqn 1
larger number is one more than twice the smaller number
Therefore,
b = 1 + 2a ----- eqn 2
Substitute eqn 2 in eqn 1
1 + 2a - a = 9
<h3>a = 8</h3>
Substitute a = 8 in eqn 1
b - 8 = 9
b = 9 + 8
<h3>b = 17</h3>
Thus the larger number is 17
Answer:
D
Step-by-step explanation:
9(3)^-4
3^2 × (3^-4)
in algebraic expression a^n × a^m = a^n+m
3^2+(-4)
3^-2
but 3^-2 = 1/3²
1/3²= 1/9
If I understand this, you have the equation 6(2x+7)-5. This is equal to 12x+37. Hope this helps.
