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Mars2501 [29]
3 years ago
14

Do anyone know how to solve this? need the answer fast.

Mathematics
1 answer:
Nikitich [7]3 years ago
6 0
The value of g^-1(-3) is the value of x that makes g(x) = -3. To find it, we can solve
.. (x +4)/(2x -5) = -3
.. x +4 = -3(2x -5)
.. 7x = 11
.. x = 11/7

The desired value is
.. (3/11)*g^-1(-3)
.. = (3/11)*(11/7)
.. = 3/7

\frac{3}{11} g^{-1}(-3) = \frac{3}{7}
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Simplify the following polynomial expression. (5x^4 - 9x^3 + 7x - 1) + (-8x^4 + 4x^2 - 3x + 2) - ( -4x^3 + 5x - 1)( 2x - 7)
Lady bird [3.3K]

Answer: 5x^{4}-37x^{3}-6x^{2} +41x-6


Step-by-step explanation:

1. You must apply the Distributive property.  You need to remember the product property of exponents: If you multiply powers with the same base, you must add the exponents. Them you have:

=5x^{4}-9x^{3}+7x-1-8x^{4}+4x^{2}-3x+2-(8x^{4}+28x^{3}+10x^{2}-35x-2x+7)\\=5x^{4}-9x^{3}+7x-1-8x^{4}+4x^{2}-3x+2-8x^{4}-28x^{3}-10x^{2}+35x+2x-7

2. Now, you must add the like terms. Then, you obtain the following result:

=5x^{4}-37x^{3}-6x^{2} +41x-6



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