ANSWER
The solution is
x=-3,y=-2
EXPLANATION
First equation
3x – 3y = –3
Second Equation:
5x – y = –13
Multiply the second equation by 3 to get:
Third equation:
15x-3y=-39
Subtract the first equation from the third equation:
![15x - 3x = - 39 - - 3](https://tex.z-dn.net/?f=15x%20-%203x%20%3D%20%20-%2039%20-%20%20-%203)
![12x = - 36](https://tex.z-dn.net/?f=12x%20%3D%20%20-%2036)
Divide both sides by 12,
![x = \frac{ - 36}{12} = - 3](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B%20-%2036%7D%7B12%7D%20%20%3D%20%20-%203)
Put x=-3 into the first equation:
![3( - 3) - 3y = - 3](https://tex.z-dn.net/?f=3%28%20-%203%29%20-%203y%20%3D%20%20-%203)
![- 9 - 3y = - 3](https://tex.z-dn.net/?f=%20-%209%20%20-%203y%20%3D%20%20-%203)
Group like terms,
![- 3y = - 3 + 9](https://tex.z-dn.net/?f=%20-%203y%20%3D%20%20-%203%20%2B%209)
![- 3y = 6](https://tex.z-dn.net/?f=%20-%203y%20%3D%206)
![y = - 2](https://tex.z-dn.net/?f=y%20%3D%20%20-%202)
The solution is
x=-3,y=-2
Income of the first account after x years:
![1,850(1.026)^x](https://tex.z-dn.net/?f=1%2C850%281.026%29%5Ex)
Income of the second account after x years:
![2,015(1.015)^x](https://tex.z-dn.net/?f=2%2C015%281.015%29%5Ex)
Equating the above tw values we get the equation:
![1,850(1.026)^x=2,015(1.015)^x](https://tex.z-dn.net/?f=1%2C850%281.026%29%5Ex%3D2%2C015%281.015%29%5Ex)
Solving the above equation for x:
![x=8](https://tex.z-dn.net/?f=x%3D8)
Answer 8 years.
Answer:
length=4 1/4
Step-by-step explanation:
- 1 3/4 + 2 1/2
- convert 2 1/2 into 2/4 since 2 is half of 4
- add the converted number and 1 3/4 fractions
- 2/4 and 3/4 added will make 1 1/4
- add 1 1/4, 2 and 1 and it will equal 4 1/4
Answer:
Standard error (S.E) = 0.048 ≅ 0.05
Step-by-step explanation:
<u>Explanation</u>:-
Given sample size 'n'=76
Given the dean who randomly selects 76 students and finds that 58 out of 76 are receiving financial aid.
Sample proportion
![p = \frac{x}{n} = \frac{58}{76} = 0.7631](https://tex.z-dn.net/?f=p%20%3D%20%5Cfrac%7Bx%7D%7Bn%7D%20%3D%20%5Cfrac%7B58%7D%7B76%7D%20%3D%200.7631)
The standard error is determined by
![S.E = \sqrt{\frac{p(1-p)}{n} }](https://tex.z-dn.net/?f=S.E%20%3D%20%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%20%7D)
Standard error is 0.048 ≅ 0.05