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zloy xaker [14]
3 years ago
11

I would like help ASAP I would like help to write this in a paragraph.

Mathematics
1 answer:
MrRa [10]3 years ago
8 0

Surface area is the area that is on the outside of a figure and will be used when you have to cover something, but a volume is an area inside an object and is used in finding the amount someone can hold within something else.

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A1 = 5 and d = 5 find the 25th term
boyakko [2]
An = a + (n - 1)d
A25 = -1 + (24)-10
A25 = -1 -240
A25 = -241
8 0
3 years ago
12 friends shared 8 small pizzas equally how much pizza did each person get?
timofeeve [1]
To get the answer you have to do 12 divided by 8
12/8=1.5
So everyone got 1 and 1/2 pizzas per person
6 0
3 years ago
Read 2 more answers
Lanie's Room Is In The Shape Of A Parallelogram. The Floor Of Her Room Is Shown And Has An Area Of 108 Square Feet. Lanie Has A
Natasha2012 [34]

Answer:

The rug will fit on the floor of her room

Step-by-step explanation:

The floor's area is given as 108

Will the rug fit this area of 108 sq. ft.?? We have to find the area of the rug and if it is less than 108, then definitely it will fit.

The rug is in the shape of a rectangle. The area of a rectangle is length times width.

Given length 10 and width 6, the area is:

Area of Rectangle = 10 * 6 = 60

Area of Rug = 60

Is 60 less than 108?? Yes, definitely!

The rug will fit on the floor of her room

6 0
3 years ago
Enter the fraction 1/5 as a decimal
aksik [14]

Answer:

.2

Step-by-step explanation:

do 1 divided into 5 in long division.

you will end up with .2

4 0
3 years ago
Read 2 more answers
What is the solution to the system of equations?
Dovator [93]

Answer:

<h2>(-10, 2, 6)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}x+3y+2z=8&(1)\\3x+y+3z=-10&(2)\\-2x-2y-z=10&(3)\end{array}\right\qquad\text{subtract both sides of the equations (1) from (2)}\\\\\underline{-\left\{\begin{array}{ccc}3x+y+3z=-10\\x+3y+2z=8\end{array}\right }\\.\qquad2x-2y+z=-18\qquad(4)\qquad\text{add both sides of the equations (3) and (4)}\\\\\underline{+\left\{\begin{array}{ccc}-2x-2y-z=10\\2x-2y+z=-18\end{array}\right}\\.\qquad-4y=-8\qquad\text{divide both sides by (-4)}\\.\qquad\qquad y=2\qquad\text{put the value of y to (1) and (3)}

\left\{\begin{array}{ccc}x+3(2)+2z=8\\-2x-2(2)-z=10\end{array}\right\\\left\{\begin{array}{ccc}x+6+2z=8&\text{subtract 6 from both sides}\\-2x-4-z=10&\text{add 4 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+2z=2&\text{multiply both sides by 2}\\-2x-z=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+4z=4\\-2x-z=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad3z=18\qquad\text{divide both sides by 3}\\.\qquad\qquad z=6\qquad\text{put the value of z to the first equation}

x+2(6)=2\\x+12=2\qquad\text{subtract 10 from both sides}\\x=-10

4 0
3 years ago
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