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olasank [31]
3 years ago
7

Worth more Points!!!!

Mathematics
2 answers:
Nana76 [90]3 years ago
8 0
8x^2+20x+24 -==----=---===---------------==============--------------============-------===========----======--=-=-=-=-=-=-=-=-=-=
Lilit [14]3 years ago
7 0
-72-4x^2+8x^3-36x/x-3

-4(18+x^2-2x^3+9x)/x-3

-4(-2x^3+x^2+9x+18)/x-3

-4(-2x^2x(x-3)-5x x(x-3)-6(x-3) )/x-3

-4 x(-(x-3) ) x (2x^2+5x+6)/x-3

-4 x (-1) x (2x^2 +5x+6)



8x^2+20x+24
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minus 4 both sides

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x=2
 
<span>the answer is 
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What is the slope of the line that passes through points (6, 7) and (4, 2)?
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The slope is 2.5!

y=2.5x-8

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If a recipe uses 1 1/2 cups of flour and makes 6 servings how many cupes of flour is in one serving
mestny [16]
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4 years ago
Which of the following is the probabilty against drawing a heart from a standard deck of 52 cards?
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3 0
3 years ago
Diagram 5 shows a right cylinder with a diameter of 2xcm. Given that the total surface area of the cylinder is 96cm³.Find the ma
Paraphin [41]

Given:

The diameter of the right cylinder is 2x cm.

The total surface area is 96 cm cube.

The radius is calculated as,

\begin{gathered} r=\frac{d}{2} \\ r=\frac{2x}{2} \\ r=x\text{ cm} \end{gathered}

The total surface area is,

\begin{gathered} S=2\pi rh+2\pi(r)^2 \\ 96=2\pi xh+2\pi(x^2) \\ h=\frac{96-2\pi(x^2)}{2\pi x} \end{gathered}

Volume is,

\begin{gathered} V=\pi(r)^2h \\ =\pi(x^2)\frac{96-2\pi(x^2)}{2\pi x} \\ =\frac{x(96-2\pi(x^2)}{2} \end{gathered}

Now, differentiate with respect to x,

\begin{gathered} \frac{dV}{dx}^{}=\frac{d}{dx}(\frac{x(96-2\pi(x^2)}{2}) \\ =\frac{d}{dx}\mleft(x\mleft(-\pi x^2+48\mright)\mright) \\ =\frac{d}{dx}\mleft(x\mright)\mleft(-\pi x^2+48\mright)+\frac{d}{dx}\mleft(-\pi x^2+48\mright)x \\ =1\cdot\mleft(-\pi x^2+48\mright)+\mleft(-2\pi x\mright)x \\ =84-3\pi(x^2)\ldots\ldots\ldots\ldots\text{.}(1) \end{gathered}

Now,

\begin{gathered} \frac{dV}{dx}=0 \\ 84-3\pi(x^2)=0 \\ x^2=\frac{16}{\pi} \\ x=\sqrt[]{\frac{16}{\pi}} \end{gathered}

Now, differentiate (1) with respect to x again,

\begin{gathered} \frac{d^2V}{dx^2}=\frac{d}{dx}(84-3\pi(x^2)) \\ =-6\pi x \\ At\text{ x=}\sqrt[]{\frac{16}{\pi}} \\ \frac{d^2V}{dx^2}=-6\pi\sqrt[]{\frac{16}{\pi}}

Since, the double derivative is negative.

So,\text{ the volume is maximum at }\sqrt[]{\frac{16}{\pi}}

So, the volume becomes,

\begin{gathered} V=\pi(x^2)h \\ V=\pi(\sqrt[]{\frac{16}{\pi}})^2h \\ V=\frac{16h}{\pi} \end{gathered}

Answer: maximum volume of the cylinder is,

6 0
1 year ago
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