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3 years ago

Graph the line with slope 2 passing through the point (-2,3).

Mathematics

2 answers:

NemiM [27]3 years ago

7 0

Find the equation using y=mx+b and what you're given in the question.
3=2(-2)+b
3=-4+b
3+4=b
7=b
The equation is y=2x+7
Hope this helps!

Dafna1 [17]3 years ago

4 0

(-2,3) with a slope of 2. You could find another point with the rise over run rule.
(-2,3) rises by 2 making it (-2,5) then it runs 1 making it (-1,5)
Your new coordinate should be (-1,5)
Now you can make a line using the coordinates of (-2,3) and (-1,5)

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3 years ago

Read 2 more answers

2. y = -2x² + 8x Axis of Symmetry: Vertex: Domain: Range:

worty [1.4K]

Answer:

Part 1) The axis of symmetry is x=2

Part 2) The vertex is the point (2,8)

Part 3) The domain is all real numbers

Part 4) The range is all real numbers less than or equal to 8

Step-by-step explanation:

we have

$y=-2x^{2}+8x$

This is a vertical parabola open downward (because the leading coefficient is negative)

The vertex represent a maximum

step 1

Find the vertex

Convert the quadratic equation in vertex form

Factor -2 leading coefficient

$y=-2(x^{2}-4x)$

Complete the square

$y=-2(x^{2}-4x+4)+8$

rewrite as perfect squares

$y=-2(x-2)^{2}+8$

The vertex is the point (2,8)

step 2

Find the axis of Symmetry

we know that

In a vertical parabola, the axis of symmetry is equal to the x-coordinate of the vertex

the vertex is the point (2,8)

therefore

The axis of symmetry is x=2

step 3

Find the domain

The domain of the quadratic equation is the interval ------> (-∞,∞)

The domain is all real numbers

step 4

Find the range

The range of the quadratic equation is the interval ------> (-∞,8]

$y\leq 8$

The range is all real numbers less than or equal to 8

5 0

3 years ago