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3 years ago

Find three solutions of the equation y = 9x - 4.

Mathematics

1 answer:

Darina [25.2K]3 years ago

7 0

First one; substitute x into the equation and see if the result equal y in the coordinate

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4x+12+2=23 Solve the multi step equation

Eduardwww [97]

Answer: x = 9/4

Step-by-step explanation:

4x+12+2=23

4x+14 = 23

4x = 9

x = 9/4

7 0

2 years ago

Read 2 more answers

Consider the first three terms of the arithmetic sequence: 7, 15, 23,... Determine d, the common difference.

ValentinkaMS [17]

Answer:

I think 47 and 55

Explanation:

I think that each number is the previous one plus 8;

7+8=15

15+8=23

23+8=31

31+8=39

So, next will be:

39+8=47

47+8=55

Is this what ur looking for?? hope this help:)

3 0

2 years ago

Prove that {(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

USPshnik [31]

First, expand the terms inside the bracket you will get

$(( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) }$

$16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

5 0

2 years ago

Quadratic Functions & Transformations 9-15 odd questions only

Eduardwww [97]

please mark me as brainliest........

follow me.........

4 0

2 years ago

PLEASE HELP OUT!!! im super lost.

Alex73 [517]

Just replace X with the given value.

X = -3

f(-3) = 5 - (-3)

f(-3) = 5 +3

f(-3) = 8

3 0

2 years ago