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3 years ago

12

one morning the temperature is -28 in Anchorage, Alaska, and 65 in Miami, Florida. How many degrees warmer was it in Miami than

Anchorage on that morning?

1 answer:

polet [3.4K]3 years ago

8 0

since the first number is negative and the 2nd is positive just add the two together

-28 + 65 = 93 degree warmer in Miami

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What is the radius of a circle whose equation is x 72 y 102 4

almond37 [142]

The circle of the given radius with equation (x-7)²+(y-10)²=4 is 2 units.

<h3>What do we mean by circles?</h3>

A circle is, in the simplest terms, a circular shape without edges or lines.

Its geometric form is that of a closed curve.

If you track a moving point in a plane while keeping a fixed distance from another point, a circle will have a closed shape.

The English word "circle" derives from the Greek word "kirks," which means "hoop" or "ring."

So, the equation for a circle in its standard form is:

(x - h)² + (y - k)² = r²

Where the radius is r and the centroid is (h, k).

The equation is: (x - 7)² + (y - 10)² = 4

This is rewritten as:

(x - 7)² + (y - 10)² = 2²

When compared to the typical form:

(h, k) = (7, 10)

The circle's radius is 2.

Therefore, the circle of the given radius with equation (x-7)²+(y-10)²=4 is 2 units.

Know more about circles here:

brainly.com/question/24375372

#SPJ4

Correct question:
What is the radius of a circle whose equation is (x-7)²+(y-10)²=4?

8 0

1 year ago

g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa

adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is $\sigma = 0.0133$

Step-by-step explanation:

From the question we are told that

The upper specification is $USL = 1.68 \ mm$

The lower specification is $LSL = 1.52 \ mm$

The sample mean is $\mu = 1.6 \ mm$

The standard deviation is $\sigma = 0.03 \ mm$

Generally the capability index in mathematically represented as

$Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]$

Now what min means is that the value of CPk is the minimum between the value is the bracket

substituting value given in the question

$Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]$

=> $Cpk = min[ 0.88 , 0.88 ]$

So

$Cpk = 0.88$

Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2

Now let assuming that

$\frac{\mu - LSL }{ 3 * \sigma } = 2$

So

$\frac{ 1.60 - 1.52 }{ 3 * \sigma } = 2$

=> $0.08 = 6 \sigma$

=> $\sigma = 0.0133$

So

$\frac{ 1.68 - 1.60 }{ 3 * 0.0133 }$

=> $2$

Hence

$Cpk = min[ 2, 2 ]$

So

$Cpk = 2$

So $\sigma = 0.0133$ is the value of standard deviation required

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