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wolverine [178]
4 years ago
13

True or false the image of the point (-8,-5) under a reflection across the y-axis is (8,-5)

Mathematics
1 answer:
kakasveta [241]4 years ago
7 0
False. A reflection over the y-axis would result in: (-8,5)
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For the pair of supply-and-demand equations, where x represents the quantity demanded in units of 1000 and p is the unit price i
Liono4ka [1.6K]

Answer:

7 and 6 respectively

Step-by-step explanation:

Firstly, we have to solve the equations simultaneously.

2x + 7p = 56

3x - 11p = -45

Multiply equation I by 3 and ii by 2

6x +21p = 168

6x - 22p = -90

Subtract the second from first to yield:

43p = 258

p = 6

Insert this in equation 1 where we have 2x + 7p = 56

2x + 7(6) =56

2x + 42 = 56

2x = 14 and x = 7

The equilibrium price is 6 and the equilibrium quantity is 7

8 0
3 years ago
Rewrite the expression in terms of the given function 1/1-sinx - sinx/1+sinx
Feliz [49]
Your question seems a bit incomplete, but for starters you can write

\dfrac1{1-\sin x}-\dfrac{\sin x}{1+\sin x}=\dfrac{1+\sin x}{(1-\sin x)(1+\sin x)}-\dfrac{\sin x(1-\sin x)}{(1+\sin x)(1-\sin x)}=\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}

Expanding where necessary, recalling that (1-\sin x)(1+\sin x)=1-\sin^2x=\cos^2x, you have

\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}=\dfrac{1+\sin x-\sin x+\sin^2x}{\cos^2x}=\dfrac{1+\sin^2x}{\cos^2x}

and you can stop there, or continue to rewrite in terms of the reciprocal functions,

\dfrac{1+\sin^2x}{\cos^2x}=\sec^2x+\tan^2x

Now, since 1+\tan^2x=\sec^2x, the final form could also take

\sec^2x+\tan^2x=\sec^2x+(\sec^2x-1)=2\sec^2x-1

or

\sec^2x+\tan^2x=(1+\tan^2x)+\tan^2x=1+2\tan^2x
7 0
4 years ago
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egoroff_w [7]

Answer:

-3

Step-by-step explanation:

Just subtract it like it was the other way around then add a minus (-)

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4 years ago
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madam [21]

The tax is 3.60, the total is 51.60


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3 years ago
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How can you recognize and interpret associations in two-way tables?
galina1969 [7]

Answer:

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