The radius of the circular cross-section of the can of soup is; 3.4cm.
<h3>What is the radius of the can of soup?</h3>
Since, the can has a height of 10cm and the volume of the can is 363cm³, it follows that the area of the circular cross-section can be evaluated as;
A = 363/10 = 36.3cm²
Hence, it follows that the radius can be evaluated as follows;
36.3 = 3.14 × r²
r² = 36.3/3.14
r² = 11.56
r = 3.4cm
Read more on volume of a cylinder;
brainly.com/question/9554871
#SPJ1
Step-by-step explanation:
Given
5x + 2x + 2 = 9x + 4
9x - 5x - 2x = 2 - 4
9x - 7x = - 2
2x = - 2
x = - 2 / 2
Therefore x = -1.
The answer is 5786 dsgsdgsa
Answer:
25%
Step-by-step explanation:
Percent change formula:
x_1 = initial value
x_2 = final value
1/4 = 0.25
