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Tema [17]
3 years ago
5

Will give brainliest to correct answer please help

Mathematics
1 answer:
tangare [24]3 years ago
6 0

Answer:

Its B

Step-by-step explanation:

I did the test on edge

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Your family goes to a Southern-style restaurant for dinner. There are 5 people in your
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x-number\ of\ people\ who\ ordered\ chicken\\5-x-number\ of\ people\ who\ ordered\ steak\\\\13x+18(5-x)=80\\13x+90-18x=80\\13x-18x=80-90\\-5x=-10\ \ \ \ \ |:-5\\x=2\\\\5-2=3\\\\a)\ 3\ of\ them\ ordered\ steak\\b)\ 2\ of\ yhem\ ordered\ chicken
4 0
3 years ago
Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adul
ddd [48]

Answer:

a) 0.194 = 19.4% probability that more than 7 preferred McDonald's

b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

50% of all young adults prefer McDonald's to Burger King when asked to state a preference.

This means that p = 0.5

12 young adults were randomly selected

This means that n = 12

(a) What is the probability that more than 7 preferred McDonald's?

P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.121

P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.054

P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.016

P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.003

P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.000

P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.121 + 0.054 + 0.016 + 0.003 + 0.000 = 0.194

0.194 = 19.4% probability that more than 7 preferred McDonald's

(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?

P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.054

P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.121

P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.193

P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.226

P(X = 7) = C_{12,7}.(0.5)^{7}.(0.5)^{5} = 0.193

P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.054 + 0.121 + 0.193 + 0.226 + 0.193 = 0.787

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?

Since p = 1-p = 0.5, this is the same as b) above.

So

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

7 0
2 years ago
Draw and upload a box plot representing the following data set: 22, 35, 18, 30, 37, 20, 40, 18, 38, 38, 23, 19, 27, 31, 34.
marshall27 [118]
See the attached image for the box plot drawing. The five number summary is given below

Min = 18
Q1 = 20
Median = 30
Q3 = 37
Max = 40

7 0
3 years ago
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For area A, the width will be √(3A/4), so for the three rugs, the widths are 6 ft, 9 ft, 12 ft. Corresponding lengths are 4/3 times that, so are 8 ft, 12 ft, 16 ft.

The rug dimensions are
.. 6 ft x 8 ft
.. 9 ft x 12 ft
.. 12 ft x 16 ft

Pick the one(s) that are on your list.
4 0
2 years ago
What is the diamiter of 37.68
Sphinxa [80]

Answer:

The diameter is 12

Step-by-step explanation:

37.68/3.14 = D π/ 3.14

D = 12  The diameter equals twelve.

7 0
3 years ago
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