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bixtya [17]
2 years ago
15

There are two golden beds. One measures 7m x 8m and the other one measures 6m x 7m.

Mathematics
1 answer:
Ivan2 years ago
4 0

Answer:

the answer is 98

Step-by-step explanation:

7×8 + 6×7 = 98

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<h2>0.001276 is the correct answer!</h2><h3 /><h3>10 x 10 x 10 x 10 x 10 = 100,000</h3><h3>127.6 ÷ 100,000 = 0.001276</h3><h3 /><h3><em>Please let me know if I am wrong.</em></h3>
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2 years ago
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What is the answer and how do you do the work
olga nikolaevna [1]
Answer: \frac{3n - 8}{4n^{2} } 

Explanation: 

First you need to factor out the GCF (greatest common factor) of the numbers, which is 8n. 
\frac{24n^{2} - 64 n}{32n^{3} }  =  \frac{8n(3n - 8)}{8n(4n^{2}) } 
The GCF cancels out on top and bottom so it becomes:
\frac{3n - 8}{4n^{2}}
6 0
3 years ago
How many meters are in 3.7 km?
Mashcka [7]

Answer:

3700 m.

Step-by-step explanation:

3.7km= 3.7* 1000

3.7 km = 3700 m

3 0
2 years ago
sons in the NHL,nts than anyone whoccomplished thiser games thanHer. Here are theRg each season:74, 45, 81, 48, 80,Working for a
vesna_86 [32]

Step 1:

In descriptive statistics, a box plot or boxplot (also known as box and whisker plot) is a type of chart often used in explanatory data analysis. Box plots visually show the distribution of numerical data and skewness through displaying the data quartiles (or percentiles) and averages.

Step 2:

To sketch a boxplot, you will need to determine the following:

Minimum

Lower quartile

Median

Upper quartile

Maximum

Step 3:

USA

First arrange the data from the least to the greatest.

14 , 26, 33, 34, 35, 38, 40, 41, 44, 46, 46, 49, 53, 66, 70.

Minimum = 14

\begin{gathered} \text{Lower quartile position = }\frac{1}{4}(n+1)^{th} \\ \text{= }\frac{15+1}{4}\text{ = }\frac{16}{4}=4^{th} \\ Q_1\text{ = lower quartile = 34} \end{gathered}

Median = 41

\begin{gathered} \text{Upper quartile position = }\frac{3}{4}(n+1)^{th} \\ =\text{ }\frac{3\text{ }\times(15+1)}{4} \\ =12^{th} \\ Q_3\text{ = upper quartile  = 49} \end{gathered}

Maximum = 70

Interquartile range IQR = 49 - 34 = 15

Canada

22, 28, 31, 31, 35, 35, 36, 39, 40, 40, 42, 49, 53, 63, 68

Minimum = 22

\begin{gathered} Q1\text{  Position = }\frac{(n+1)^{th}\text{ }}{4}\text{ = }\frac{16}{4}th=4^{th} \\ Q_1\text{ = 31} \end{gathered}

Median = 39

\begin{gathered} UpperquartileQ_{_3\text{ }}\text{ = 49} \\  \end{gathered}

Maximum = 68

Interquartile range = 49 - 31 = 18

8 0
1 year ago
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