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Delicious77 [7]
4 years ago
12

Amber determined that the expression -1/2 divided by -41/15 is equivalent to 15/82. Which statement describes the process Amber

could have used?
Mathematics
2 answers:
ddd [48]4 years ago
5 0
Amber could have used cross multiplication.

Have a great day!!!!
Naya [18.7K]4 years ago
4 0

Answer:

Step-by-step explanation:

Idk i need help

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You buy shrimp at the market.
jeka57 [31]

Answer:

$7 a pound

Step-by-step explanation

$35 dollars in total two 2.5 pounds is 2 x 2.5 = 5 then its 35/5=$7

7 0
4 years ago
In 2005, 0.76% of all airline flights were on-time. If we choose a simple random sample of 2000 flights, find the probability th
marissa [1.9K]

Answer:

Step-by-step explanation:

Here X no of flight that reach on time has two outcomes only and each trial is independent of the other.

Since sample size is large we approximate to normal with mean =np and variance =npq

i.e. X is N(152,19.10)

Z=\frac{x-152}{19.1} is used for converting to std normal variate

Continuity correction of 0.5 on either side of interval would be applied for x

a) P(X\geq 79%) = P(X\geq 1580)\\=P(X\geq 1579.5)\\=P(Z\geq 3.12)

=0.00

b)P(X\leq 1580)\\=P(X\leq 1580.5)\\=P(Z\leq 3.17)\\==1.00

c) p is N(0.76, sqrtpq/n)=N(0.76,0.0095)

P(p diff>0.03) =

P(Z>\frac{0.03}{0.0095} \\=P(Z>3.16)=0.00

7 0
4 years ago
What is the intersection of AC and plane Q?
Flura [38]
The answer is point B!! hope this helped
4 0
3 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
zheka24 [161]
<h2>Hello!</h2>

The answer is:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we  have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation, we have:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

We have that the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

Hence, we have that:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

4 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the point (-2 , 7) and has a slope of zero
melomori [17]

Answer:

7 = 0(-2) + b

Step-by-step explanation:

4 0
4 years ago
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