Answer:
there are 70 possible choices for the four locations to apply the new ointment
Step-by-step explanation:
Since we have a total of 8 locations ( 4 to the new ointment and 4 to the control) , each one can be chosen and since the order of the locations that are chosen for the new ointment is not relevant , then we know that the number of choices is given by the number of combinations of 4 elements in 8
number of combinations = 8 possible locations to the first ointment * 7 possible locations to the second ( since the first one was already located) * 6 to the third * 5 locations for the fourth / number of times the same combination is repeated ( the same locations but in different positions) = 8*7*6*5 / (4 possible positions for the first ointment* 3 possible positions to the second ointment (since the first one was already located * 2 possible positions of the third * 1 possible position of the fourth)
therefore
number of combinations = 8*7*6*5/(4*3*2*1 ) = 8!/((8-4)!*4!) = 70 possible combinations
thus there are 70 possible choices for the four locations to apply the new ointment
Answer:
I count 10 triangles.....
Answer:
X=0
(8,7)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Mines came up as 79.78 but ion think that’s right
Answer:
C is correct
Step-by-step explanation:
Given: System of linear inequality
First we will draw the graph of system of equation and then see the correct option.
Equation 1:
We will make the table.
x : -2 0 2
y : 1 0 -1
Test Point: (0,4)
0<-2 ( False )
Shaded area away from (0,4)
Equation 2:
We will make the table.
x : -2 0 2
y : -1 3 7
Test Point: (0,4)
4≥3 ( True )
Shaded area towards (0,4)
Please see attachment for graph.
Hence, C is common shaded area (region)
