N-acetyltyrosine ethyl ester may likely have a higher Vmax.
<h3>How are the Km and Vmax of an enzyme and substrate related?</h3>
Km is inversely proportional enzyme affinity for substrate. The lower the Km, the higher the enzyme affinity for substrate and vice versa.
Vmax is the maximum velocity of the reaction when the enzyme is fully saturated with substrate.
Based on the Km values, chymotrypsin has higher affinity for N-acetyltyrosine ethyl ester, thus, N-acetyltyrosine ethyl ester may likely have a higher Vmax.
In conclusion, the Vmax is the maximum velocity of an enzyme-catalyzed reaction.
<em>Note that the complete question is given below:</em>
<em>The Km for the reaction of chymotrypsin with N-acetylvaline ethyl ester is 8.8 x 10-2 M, and the Km for the reaction of chymotrypsin with N-acetyltyrosine ethyl ester is 6.6 x 10-4 M.</em>
<em>Which of the following substrates is likely to give a higher value for Vmax?</em>
Learn more about Km and Vmax at: brainly.com/question/16108691
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Answer: -10
Step-by-step explanation: From the start of the equation, we know it must factor to something like (3m + x)(n+y), because the first term must be 3mn. Now, for the next term to be -6n, y must be -2, and for the third term to be 5n, x must be positive 5. So we end up with (3m+5)(n-2). If we factor this out, we get 3mn-6m+5n-10, meaning the final term is -10.
the answer to the question is F= -5.37
Answer:
67 1/2 is a mixed number
Step-by-step explanation:
The volume of a prism, is the area of the cross section X the length:
In this case it is base × height × length:
6 × 4.5 × 2.5 = 67.5cm^3
= 67 1 / 2 as a mixed number