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tia_tia [17]
3 years ago
7

Range f (x)=3x-12. Domain is (-2,2)

Mathematics
1 answer:
baherus [9]3 years ago
6 0
<span>Interpretation of question: Find the range, given the f(x) = 3x - 12 and the domain is from (-2,2).
</span>
Since the function is linear, it will always be increasing from left to right.

We can get the lower and upper bounds of our function's range by plugging in the lower and upper bounds of the domain into the function.

1) Plug -2 into the function.
3(-2) - 12 = -18

2) Plug 2 into the function.
3(2) - 12 = -6

The range is (-18, -6).

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ΔCAR has coordinates C (2, 4), A (1, 1), and R (3, 0). A translation maps point C to C' (3, 2). Find the coordinates of A' and R
shutvik [7]

Answer:

A'= (2,-1) and R'=(4,-2) under this translation.

Step-by-step explanation:

A translation in R^{2} is a mapping T from R^{2} to R^{2}  defined by T(x,y) = (x + v_1,y+v_2), where v=(v_1,v_2) is a fixed vector in R^{2}.

From the problem we know that T(2,4)=(3,2), so we need to find the values v_1 and v_2 such that  T(2,4) = (2 + v_1,4+v_2)=(3,2), so 3=2 + v_1 and 4+v_2=2, thus v_1=1 and v_2=2.

Then T(x,y) = (x + 1,y-2) and  

T(1,1)=(1+1,1-2)=(2,-1)=A'

T(3,0)=(3+1,0-2)=(4,-2)=R'

Therefore A'= (2,-1) and R'=(4,-2). The triangles CAR and C'Q'R' are shown in the figure below.

7 0
3 years ago
What is one and a half added to three and a half?
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