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kompoz [17]
2 years ago
15

Answer these questions

Mathematics
1 answer:
Firdavs [7]2 years ago
6 0

Answer:

well well well

Step-by-step explanation:

dont cheat on live classwork pls

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Johnnas reading rate is 150 words per minute she is reading a 364 page book that has about 275 words on each page at this rate w
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11 hrs 1 min (i think so based on math)

Step-by-step explanation:

If Johnna's reading rate is 150 words per min and there are 364 pages with about 275 words, you need to multiply 364 and 275 to get 100100 and divide that by 150 to get 667.3333333 round to the nearest tenth which will give you 667.3 and divide that by 60 because there are 60 minutes in an hour to get 11.12222222 and round that to the nearest tenth to get 11.1 which means it will take Johnna 11 hours and 1 minute to read the book.  I hope this is correct I'm really sorry if it isn't. :P

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Could mud wrestling be the cause of a rash contracted by Washington State University students in the spring of 1992? Physicians
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The best and most correct answer among the choices provided by the question is </span><span>A. Between 0.05 and 0.01 </span> .    
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33

Step-by-step explanation:

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Consider a uniform distribution from aequals4 to bequals29. ​(a) Find the probability that x lies between 7 and 27. ​(b) Find th
weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

P(c \leq x \leq d) = \frac{d - c}{b - a}

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So c = 7, d = 27

P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8

80% probability that x lies between 7 and 27.

​(b) Find the probability that x lies between 6 and 13. ​

So c = 6, d = 13

P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

​So c = 9, d = 20

P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So c = 11, d = 18

P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28

28% probability that x lies between 11 and 18.

3 0
3 years ago
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