So this is trig, and when it comes to right (90°) triangles, it's imperative that you know:
SOH-CAH-TOA
Sine (x) = Opposite/Hypotenuse
Cosine (x) = Adjacent/Hypotenuse
Tangent (x) = Opposite/Adjacent
*hypotenuse is always the largest side, and the one opposite the 90° angle in right triangles
therefore we'll use SOH, because the opposite of x (O) and the hypotenuse (H) are given:
Sine (x) = Opposite/Hypotenuse
Sine (x) = 32/58 = 16/29 = 0.552
Sine (x) = 0.552
now we use something called arc-sine, or

it's basically a fancy function of most advanced calculators, so we'll plug it in as:

x = 33.49° --> answer B) is correct
The answer is C because the tulips go up by 6 everytime the roses go up by 4
Step-by-step explanation:
The number n is - 5
Because the sum = 8 + (-5) = 3
After multiply by - 4 = 3 x - 4 = - 12
Option A is the correct answer
Answer :
1 one, it's one hoped this help !
Answer:
Phillipa rode the most in May and rode the least in March.
Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March
Step-by-step explanation:
Given:
In April, Phillipa rode 13 . 5 + 8 . 7 + 11 . 1 miles on her bicycle. In March, she rode ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 miles, and in May, she rode 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) miles.
To find: the month when she rode the most and the month when she rode the least
Solution:
Distance travelled by Phillipa on her cycle in April = 13 . 5 + 8 . 7 + 11 . 1 = 65 + 56 + 11 = 132 miles
Distance travelled by Phillipa on her cycle in March = ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 =
miles
Distance travelled by Phillipa on her cycle in May = 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) = 4 × 132 = 528 miles
So, she rode the most in May and rode the least in March
Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March