Question

What is the degree measure of x in this triangle?

Answer 1

So this is trig, and when it comes to right (90°) triangles, it's imperative that you know:
SOH-CAH-TOA

Sine (x) = Opposite/Hypotenuse
Cosine (x) = Adjacent/Hypotenuse
Tangent (x) = Opposite/Adjacent

*hypotenuse is always the largest side, and the one opposite the 90° angle in right triangles

therefore we'll use SOH, because the opposite of x (O) and the hypotenuse (H) are given:

Sine (x) = Opposite/Hypotenuse
Sine (x) = 32/58 = 16/29 = 0.552
Sine (x) = 0.552
now we use something called arc-sine, or
${(sin)}^{ - 1}$
it's basically a fancy function of most advanced calculators, so we'll plug it in as:
$x = {(sin)}^{ - 1} (0.552)$
x = 33.49° --> answer B) is correct