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valkas [14]
3 years ago
10

What is the degree measure of x in this triangle?

Mathematics
1 answer:
Crank3 years ago
4 0
So this is trig, and when it comes to right (90°) triangles, it's imperative that you know:
SOH-CAH-TOA

Sine (x) = Opposite/Hypotenuse
Cosine (x) = Adjacent/Hypotenuse
Tangent (x) = Opposite/Adjacent

*hypotenuse is always the largest side, and the one opposite the 90° angle in right triangles

therefore we'll use SOH, because the opposite of x (O) and the hypotenuse (H) are given:

Sine (x) = Opposite/Hypotenuse
Sine (x) = 32/58 = 16/29 = 0.552
Sine (x) = 0.552
now we use something called arc-sine, or
{(sin)}^{ - 1}
it's basically a fancy function of most advanced calculators, so we'll plug it in as:
x =  {(sin)}^{ - 1} (0.552)
x = 33.49° --> answer B) is correct
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Step-by-step explanation:

Formula = (N + 1 / 2th) term

So,

Total numbers (N) = 4

Now,

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<em>If</em><em> </em><em>you</em><em> </em><em>like</em><em> </em><em>it</em><em> </em><em>plz</em><em> </em><em>make</em><em> </em><em>me</em><em> </em><em>brainliest</em>

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3 years ago
How many 16-ounce bottles would be needed to hold the same total amount of water 56 bottles that each holds 20 ounces
snow_lady [41]

70 bottles will hold 16 ounces amount same as 56 bottles hold 20 ounces.

Step-by-step explanation:

Given,

56 bottles hold 20 ounces each.

Total amount 56 bottles hold= 56x20

Total amount hold by 56 bottles= 1120 ounces

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Total amount hold by x bottles = 16x

According to the given statement both amounts are same;  

16x=1120\\Dividing\ both\ sides\ by\ 16\\\frac{16x}{16} = \frac{1120}{16} \\x=70

70 bottles will hold 16 ounces amount same as 56 bottles hold 20 ounces.

Keywords: Division, Multiplication

Learn more about division at:

  • brainly.com/question/2035523
  • brainly.com/question/2088305

#LearnwithBrainly

6 0
3 years ago
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gavmur [86]
The answer is so false
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The glee club needs to raise money for the spring trip to Europe, so the members are assembling holiday wreaths to sell. Before
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Step-by-step explanation:

7 0
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A toxic radioactive substance with the density of 4 mg/cm² is detected in the been detected in the ventilating ducts that was us
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The formula for half-life is:

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A is the amount remaining, P is the initial amount, t is the time that has passed, and h is the half-life of the substance.  Plug in the values that you know and solve:

4 = P(0.5)^{35/20} \\ \\ 4 = P(0.5)^{1.75} \\ \\ P = \frac{4}{0.5^{1.75}} \\ \\ P \approx 13.4543426441

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