So the car is moving at 651 revolutions per minute, with wheels of a radius of 18inches
so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"
now, what's the linear velocity, namely, the arc covered per minute
well
now, how much is that in miles/hrs? well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr
thus
notice, after all the units cancellations, you're only left with mi/hrs
A study of 600 college students taking statistics 101 revealed that 54 students received the grade of
a. Typically 10% of the class gets an A
b. The difference between this group of students and the expected value is not significant at the 0.05 level. what does this mean in this case?
Your answer would mean that, =====> The probability of getting an A is 10% and only 9% got an A, in this study. The difference is less than 5% therefore, in this case, it is not significant.
Hope that helps!!!! : )
Answer:
-5
Step-by-step explanation:
<h2>Explanation</h2><h2></h2><h2>He can use the 2 pennies in 3 ways, take none, take 1 or take 2</h2><h2>He can use the 3 nickels in 4 ways, take none, take 1, etc</h2><h2>the dime in 2 ways,</h2><h2>and the quarters in 3 ways</h2><h2 /><h2>total number of ways = (3)(4)(2)(3) = 72</h2><h2>but that includes taking none of any coins,</h2><h2 /><h2>so number of ways to use the coins is 71</h2><h2 /><h2>Here is a little silly computer program that finds and lists all the possible sumes</h2><h2 /><h2>10 for p = 0 to 2</h2><h2>20 for n = 0 to 3</h2><h2>30 for d = 0 to 1</h2><h2>40 for q = 0 to 2</h2><h2>50 sum = p+5*n+10*d+25*q</h2><h2>60 print sum,</h2><h2>70 next q</h2><h2>80 next d</h2><h2>90 next n</h2><h2>100 next p</h2><h2>>run</h2><h2>0 25 50 10 35 60 5 30 55 15 40 65 10 35 60 20</h2><h2>45 70 15 40 65 25 50 75 1 26 51 11 36 61 6 31</h2><h2>56 16 41 66 11 36 61 21 46 71 16 41 66 26 51 76</h2><h2>2 27 52 12 37 62 7 32 57 17 42 67 12 37 62 22</h2><h2>47 72 17 42 67 27 52 77</h2><h2 /><h2>Notice there are duplications,</h2><h2>e.g. picking 2 nickels or 1 dime yields the same sum</h2><h2 /><h2>All you have to do is eliminate all duplications, and not count the 0</h2><h2>I think there are 47 or them</h2>
