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iren [92.7K]
3 years ago
14

Jenny runs 1 mi to the northeast then 1 mi south. Graphically find her net displacement

Mathematics
1 answer:
Umnica [9.8K]3 years ago
7 0

SOLUTION:

from OA=AB

\theta +\theta 45=180

2\theta =180-45

\theta =\frac{180-45}{2}=67.5

from sin rule,

\frac{OA}{sin\theta }=\frac{AB}{sin\theta }=\frac{OB}{sin45}

\therefore \frac{1}{sin67.5}=\frac{1}{sin67.5}=\frac{OB}{sin45}

\therefore OB=\frac{sin45}{sin67.5}=0.765366864730ml

\therefore net displacement OB=o.77ml

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What is equilibrium if autonomous expenditures are $2,000 and the mpe is 0. 5?
STALIN [3.7K]

The equilibrium level if autonomous expenditures are $2,000 and the mpe is 0. 5 is $4000.

<h3>How to calculate the equilibrium?</h3>

From the information given, the autonomous expenditures are $2,000 and the mpe is 0. 5.

Here, the equilibrium level will be:

= 2000/(1 - 0.5)

= 2000/0.5

= 4000

In conclusion, the correct option is $4000.

Learn more about expenditure on:

brainly.com/question/935872

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3 0
2 years ago
With one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the en
GuDViN [60]

Answer:

P = 0.1447

Step-by-step explanation:

Given

n = 7000 -- total

d = 180 --- defective

r = 6 --- selected

Required

The probability of rejecting the batch

This means that at least one of the selected piece is defected.

So, we first calculate the probability that all the selected piece are accepted.

So, we have:

Pr = \frac{7000 - 180}{7000} * \frac{6999 - 180}{6999}* \frac{6998 - 180}{6998}* \frac{6997 - 180}{6997}* \frac{6996 - 180}{6996}* \frac{6995 - 180}{6995}

The denominator decreases by 1 because it is a probability without replacement; 180 is subtracted from the numerator to represent the number of non-defective CDs

So, we have:

Pr = \frac{6820}{7000} * \frac{6819}{6999}* \frac{6818}{6998}* \frac{6817}{6997}* \frac{6816}{6996}* \frac{6815}{6995}

Pr = 0.8553

Using the complement rule, the probability that the batch will be rejected is:

P = 1 - 0.8553

P = 0.1447

8 0
2 years ago
How many hours did I work if I worked 7 hours and 30 minutes a day, for 15 days?
baherus [9]

Answer:

112 hours and 50 mins

Step-by-step explanation:

Numbers of mins worked in a day = 7×60+30 =450 mins

Now number of mins worked in 15 days = 450×15

= 6750 mins

to convert mins into hours divide by 60

6750÷60 = 112.50

that means total number of hours worked in 15 days = 112 hours and 50 mins

8 0
3 years ago
WILL GIVE U BRAINLIEST ♡ Rationalize the denominator of fraction with numerator square root of -36 divided by (2-3i)+(3+2i)
Dmitriy789 [7]

Answer:

-  \frac{3}{13}  +  \frac{15i}{13}

Step-by-step explanation:

\frac{ \sqrt{ - 36} }{(2 - 3i) + (3 + 2i)}

Set up equation

Step 1: Simplify

\frac{6i}{5 - i}

Step 2:Multiply by conjugate

\frac{6i}{5 - i}  \times  \frac{5 + i}{5 + i}

Step 3:Simplify

\frac{30i + 6 {i}^{2} }{ {i}^{2} - 5 {}^{2}  }

We can reduce this and we must make the imaginary number and real number serpate equations.

-  \frac{6}{26}  +  \frac{30i}{26}

Reduce each by 2

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7 0
2 years ago
I need help with this problem.
Phantasy [73]
Csc^2x-cot^2x=1

Here is why

csc^2x=1+cot^2x

so:
1+cot^2x-cot^2x=1
1=1

6 0
2 years ago
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