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Juli2301 [7.4K]
3 years ago
7

Solve for X A: 12.5 B: 5 C: 6

alt="\sqrt{3}" align="absmiddle" class="latex-formula">
D:12

Mathematics
2 answers:
Olenka [21]3 years ago
6 0

bear in mind that, a perpendicular line stemming from the right-angle like so, creates three similar triangles, a <u>large</u> one, containing the other two smaller ones, a <u>medium</u> and a <u>small</u>.

so.. .we can just use the medium and small proportions.

Check the picture below.

Afina-wow [57]3 years ago
4 0

Answer:

<h2>D. 12</h2>

Step-by-step explanation:

<em>(LOOK AT THE PICTURE)</em>

ΔADC and ΔCDB are similar (AAA). Therefore the corresponding sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD=16,\ CD=x,\ DB=9

Substitute:

\dfrac{16}{x}=\dfrac{x}{9}          <em>cross multiply</em>

x^2=(9)(16)\to x=\sqrt{(9)(16)}\\\\x=(\sqrt9)(\sqrt{16})\\\\x=(3)(4)\\\\x=12

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