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Shkiper50 [21]
3 years ago
10

) a 200 gallon tank initially contains 50 gallons in which are dissolved 5 pounds of salt. the tank is flushed by pumping pure w

ater into the tank at a rate of 3 gallons per minute and a well-mixed solution is pumped out at a rate of 2 gallons per minute. compute the time when the tank has filled, then write the initial value problems which describes amount of salt in the tank at any time before the tank is full. you need not solve the equation.
Mathematics
1 answer:
bulgar [2K]3 years ago
6 0
(a) The 150 gallons of empty space in the tank are being filled at the rate of 1 gallon per minute. The tank will be filled after 150 minutes.

(b) s(0) = 5
.. s'(t) = -2s(t)/(50 +t)
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Answer:

We conclude that the sodium content is same as what the nutrition label states.

Step-by-step explanation:

We are given that the nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium.

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<u><em /></u>

<u><em>Let </em></u>\mu<u><em> = average sodium content.</em></u>

So, Null Hypothesis, H_0 : \mu = 1100 milligrams      {means that the sodium content is same as what the nutrition label states}

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The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                    T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}  ~ t_n_-_1

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            n = sample of packages of Oriental Spice Sauce = 40

So, <u><em>test statistics</em></u>  =  \frac{1088.64-1100}{\frac{234.12}{\sqrt{40}}}  ~ t_3_9

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The value of z test statistics is -0.307.

<em>Since, in the question we are not given the level of significance so we assume it to be 5%. </em><em>Now, at 0.05 significance level the t table gives critical values of -2.0225 and 2.0225 at 39 degree of freedom for two-tailed test.</em><em> </em>

<em>Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the sodium content is same as what the nutrition label states.

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