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3 years ago

Elimination 3x + 4y = 2 4x - 4y = 12

Mathematics

1 answer:

pishuonlain [190]3 years ago

6 0

To do this, add the equations together like this,

3x + 4y = 2 plus

4x - 4y = 12

-x = 14

Multiply the negative sign to both sides because the x cannot be a negative.

x = -14

Now plug in -14 for a x value in one equation, like this to get the y value:

3(-14) + 4y = 2

-42 + 4y = 2

Add 42

4y = 44

y = 11

Your x and y values are:

x = -14

y = 11

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Write an equation of a line in slope intercept form that is perpendicular to y = -4x -2 and passes through the point (-16, -11).

NISA [10]

Y = -4x - 2
P (-16, -11)
a = -4, b = 0, c = -2
m = -a/b
m = -(-4)/(-2)
m = 4/(-2)
m = -2

y-yo = m(x-xo)
y-(-11) = -2[x-(-16)]
y+11 = -2(x+16)
y+11 = -2x-32
2x+y+11+32 = 0
2x+y+43 = 0

A outra questão é semelhante.

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3 years ago

Find the centre of the circle<br><br> x^2 + y^2 + 4x - 6y = 12

zhannawk [14.2K]

Answer:

centre = (- 2, 3 )

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

given

x² + y² + 4x - 6y = 12 ( collect x/ y terms )

x² + 4x + y² - 6y = 12

using the method of completing the square

add ( half the coefficient of the x/ y terms)² to both sides

x² + 2(2)x + 4 + y² + 2(- 3)y + 9 = 12 + 4 + 9

(x + 2)² + (y - 3)² = 25 ← in standard form

with centre (- 2, 3 ) and r = $\sqrt{25}$ = 5

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2 years ago

Mr. Bender is putting his middle school band students into O points

baherus [9]

Answer:

Step-by-step explanation:

the answer is 8 because is the oly no that if divided by any number that the answer will be given and it is the largest number that can go in 32 and 40

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4 years ago

What is 8/6 × 5/8?<br>

prohojiy [21]

Answer:

The answer to this is 5/6

Step-by-step explanation:

Use cross-multiply which cancels 8 out

now you are left with, 5/6

Hope this Helped!!!

~Shane

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