3-7 Please Help BRAINLEST

Mathematics

2 answers:

Misha Larkins [42]3 years ago

7 0

Answer : r = 7
Using transposition method taking 10 to LHS will be -10
= r = 17-10
r = 7
Verification :
17 = r + 10
17 = 7+10
17 = 17
HENCE, LHS=RHS

9966 [12]3 years ago

5 0

Hi there! Hopefully this helps!

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<h2>Answer: r = 7.</h2><h2>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h2>

$17 = r + 10$

Swap sides so that all variable terms are on the left hand side.

$r + 10 = 17$

Subtract 10 from both sides.

$r = 17 - 10$

<h2>Subtract 10 from 17 to get, you guessed it, 7!</h2>

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Elden [556K]

Answer:

(d) m∠AEB = m∠ADB

Step-by-step explanation:

The question is asking you to compare the measures of two inscribed angles. Each of the inscribed angles intercepts the circle at points A and B, which are the endpoints of a diameter.

<h3>applicable relations</h3>

Several relations are involved here.

The measures of the arcs of a circle total 360°
A diameter cuts a circle into two congruent semicircles
The measure of an inscribed angle is half the measure of the arc it intercepts

<h3>application</h3>

In the attached diagram, we have shown inscribed angle ADB in blue. The semicircular arc it intercepts is also shown in blue. A semicircle is half a circle, so its arc measure is half of 360°. Arc AEB is 180°. That means inscribed angle ADB measures half of 180°, or 90°. (It is shown as a right angle on the diagram.)

If Brenda draws angle AEB, it would look like the angle shown in red on the diagram. It intercepts semicircular arc ADB, which has a measure of 180°. So, angle AEB will be half that, or 180°/2 = 90°.

The question is asking you to recognize that ∠ADB = 90° and ∠AEB = 90° have the same measure.

m∠AEB = m∠ADB

_____

<em>Additional comment</em>

Every angle inscribed in a semicircle is a right angle. The center of the semicircle is the midpoint of the hypotenuse of the right triangle. This fact turns out to be useful in many ways.