Question

Consider a cell that requires much more ribose5‑phosphate than NADPH. The cell needs ribose 5‑phosphate but has a relatively high concentration of NADPH and a low concentration of NADP + . These conditions may occur in rapidly dividing cells. What is the fate of glucose 6‑phosphate, glycolytic intermediates, and pentose phosphate pathway intermediates in this cell? Under the given conditions, all triose phosphates are converted to pyruvate by the glycolytic pathway. A. One molecule of glyceraldehyde 3‑phosphate and two molecules of fructose 6‑phosphate are used to generate three molecules of ribose 5‑phosphate. B. Most of the glucose 6‑phosphate enters the glycolytic pathway and is converted to fructose 6‑phosphate and glyceraldehyde 3‑phosphate. C. Most of the glucose 6‑phosphate enters the pentose phosphate pathway. D. Glycolytic intermediates can only enter the pentose phosphate pathway through conversion to pyruvate and subsequent gluconeogenesis. E. The oxidative pentose phosphate pathway reaction catalyzed by glucose 6‑phosphate dehydrogenase is slowed down.

Answer 1

Answer:

B- Most of the glucose 6-phosphate enters the pentose phosphate pathway.

Explanation:

Since the cell requires much more ribose 5- phosphate than NADPH, then it would lead the glucose 6-phosphate down the oxidative phosphate pathway to create ribulose 5-phosphate, which can be isomerized to ribose 5-phosphate depending on the cell state.