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ioda
3 years ago
14

PLEASE HURRY!!Given the following graph of a system of inequalities, which statement below is true of the point(5,-5)?

Mathematics
2 answers:
OverLord2011 [107]3 years ago
6 0

Answer:

The answer is D.

GREYUIT [131]3 years ago
5 0

Answer with explanation:

Select two points on the line to find the equation of the line.

Taking two points ,(6,8) and (-3, -7)  on the line.

→Equation of Line passing through two points (x_{1},y_{1}),(x_{2},y_{2}) is given by

\rightarrow \frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\\rightarrow \frac{y-8}{x-6}=\frac{-7-8}{-3-6}\\\\3y-24=5x-30\\\\5x-3y-6=0

If you will write this in terms of inequality

5x-3y>6

→Second line passes through, (0,-4) and (9,-1).

Equation of this line will be

\frac{y-(-4)}{x-0}=\frac{-1-(-4)}{9-0}\\\\9y+36=3x\\\\3x-9y-36=0\\\\x-3y-12=0

If you will write this in terms of inequality,it will be

x-3y>12

Option A

It satisfy both the inequality and is part of solution set.

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You are choosing between two plans at a discount warehouse. Plan A offers an annual membership fee of ​$30 and you pay 90​% of t
docker41 [41]

The cost for plan A and plan B at a discount warehouse is $57 and $153 respectively.

<h3>Equation</h3>

Plan A:

  • Membership fee = $30

Manufacturer's recommended list price = 90%

= 90% × 30

= 0.9 × 30

= $27

Total cost of plan A = $30 + $27

= $57

Plan B:

  • Membership fee = $90

Manufacturer's recommended list price = 70%

= 70% × 90

= 0.7 × 90

= $63

Total cost of plan B = $90 + $63

= $153

Therefore, the cost for plan A and plan B at a discount warehouse is $57 and $153 respectively.

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4 0
2 years ago
Solve the system shown.
krek1111 [17]
1. Rewrite the system:

 x+12y=68  (i)
 x=8y-12   (ii)

 2. Let's substitute the equation (ii) into the equation (i):

 x+12y=68
 (8y-12)+12y=68

 3. Then, you have:

 8y-12+12y=68

 4. When you clear "y", you have:

 20y-12=68
 20y=68+12
 20y=80
 y=80/20
 y=4

 5. You already have the value of "y". Now, you must substitute this value into the equation (ii):

 x=8y-12
 x=8(4)-12
 x=32-12
 x=20

 6. Therefore, the result is:

 x=20
 y=4
3 0
4 years ago
If a five digit number is rounded to the ten thousands place is it possible for the rounded number to be a six digit number.
Bingel [31]
When rounding a number, the digit of the number can be increased up to 1, but the digit won't be decreased. So, it is possible to round a five digit number into six digit number. But to increase the number digit, the number should be rounded up. To be rounded up, a number should have value 5 or more.
4 0
4 years ago
Sjsbwjsjehgshdisiwhbdbfjsiwjwb dvdhdiejbef
Alika [10]

Answer:

x =52

Step-by-step explanation:

bith angels together make 180° so 180-128=52

8 0
3 years ago
Let g(x) = 2x and h(x)= x^2 -4. find (g o h)(0)
finlep [7]
The answer is -8

====================================================

Explanation:

There are two ways to get this answer

Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8

-----------------------

The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4

g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8

Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8

Regardless of which method you use, the answer is -8

5 0
3 years ago
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