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3 years ago

What logarithmic equation is equivalent to 3^2=9

Mathematics

1 answer:

erik [133]3 years ago

8 0

Log3 9=2

Explanation:
logo a= n <—> a = b^n

—-> 3^2 = 9 —> log3 9= 2

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A scale drawing of a rectangular painting has a scale factor of 1:4 which statements are true

vovikov84 [41]

Answer:

object have been reduced by a factor of 4 on paper or the drawing have been increased by a factor of 4 on land .

Step-by-step explanation:

What a scale factor of 1:4 means.

Simply it means that the reals size of the object on land have been reduced in the drawing in the paper.

Now for scale factor of 1:4 in particular it means that the object have been reduced by a factor of 4 on paper or the drawing have been increased by a factor of 4 on land .

Example if the drawing has measurements of 4 inches on paper, then on land it will be 16 inches

5 0

3 years ago

Using the order of operations, what should be done first to evaluate 12+(-6)(3)+(-2)?

sesenic [268]

Answer:

hello there...

you know BODMAS for sure

First brackets then of then divi then multi then add and then subtract

going by BODMAS

we need to first of all multiply of -6 and 3

hence ans is multiplying -6 and 3

( option 1 Is wrong by the equation u sent if the equation is correct then ans is which given bur by options I think equation is wrong becoz I don't see divide symbol)

7 0

3 years ago

Find the measurements of the numbered angles in each isosceles trapezoid.

SSSSS [86.1K]

Answer:

∠1 = 96°

∠2 = 84°

∠3 = 84°

Step-by-step explanation:

∠1 = 96°

∠2 = ∠3

∠1 + 96 + ∠2 + ∠3 = 360°

∠2 = (360 - 96 - 96)/2 = 84°

∠3 = 84°

8 0

3 years ago

Help pleaseeeeeeeeeeeeeeeeeeeeeee

bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$