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erik [133]
3 years ago
14

What logarithmic equation is equivalent to 3^2=9

Mathematics
1 answer:
erik [133]3 years ago
8 0
Log3 9=2

Explanation:
logo a= n <—> a = b^n

—-> 3^2 = 9 —> log3 9= 2
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Help please with algebra problem
Strike441 [17]
Number of weekend minutes used: x
Number of weekday minutes used: y

This month Nick was billed for 643 minutes:
(1) x+y=643

The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44

We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44

Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y

Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44

Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72

Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243

Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400


Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
6 0
3 years ago
Sfewrthewbtwebrhwebrthbweytbewhibthewghuelbtrueruhewbthujbrultbhrt
Tju [1.3M]
This fjzbwndjsjenskfkfnf I’m dababy
3 0
3 years ago
Mr. Williams is building a sand box for his children. It costs $228 for the sand if he builds a rectangular-sand box with dimens
Andru [333]

Answer:  The correct option is (C) $342.

Step-by-step explanation:  Given that Mr. Williams is building a sand box for his children and is costs $228 for the sand if he builds a rectangular-sand box with dimensions 9 ft by 6 ft.

We are to find the cost of the sand if he decides to increase the size to 13\frac{1}{2}~\textup{ft by }9~\textup{ft}.

Since the box is empty from inside, so we will be considering the perimeter of the box, not area.

The perimeter of the rectangular-sand box with dimensions 9 ft by 6 ft is

P_1=2(9+6)=30~\textup{ft},

and the perimeter of the rectangular-sand box with dimensions 13\frac{1}{2}~\textup{ft by }9~\textup{ft}. is

P_2=2\left(13\dfrac{1}{2}\times9\right)=2(13.5\times9)=45~\textup{ft}.

Now, we will be using the UNITARY method.

Cost of sand for building rectangular-sand box with perimeter 30ft = $228.

So, cost of  sand for building rectangular-sand box with perimeter 1 ft will be

\$\dfrac{228}{30}.

Therefore, the cost of sand for building rectangular-sand box with perimeter 45 ft is given by

\$\dfrac{228}{30}\times45=\$342.

Thus, the required cost of the sand is $342.

Option (C) is CORRECT.

3 0
3 years ago
Read 2 more answers
Please help, will give 10 points.
enot [183]

Answer:

length is 770 width is 410

Step-by-step explanation:

6 0
3 years ago
Using the completing-the-square method, rewrite f(x) = x2 − 6x + 2 in vertex form.
Irina18 [472]

Answer:

f(x)=(x-3)^2-7

Step-by-step explanation:

Vertex form: f(x) = a(x-h)^2+k

x^2-6x+9+2=f(x)+9

(x-3)^2+2=f(x)+9

f(x)=(x-3)^2-7



8 0
3 years ago
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