What's the answer for this question?

Mathematics

2 answers:

nikklg [1K]2 years ago

8 0

Answer:

6 but im not really sure

Step-by-step explanation:

Black_prince [1.1K]2 years ago

4 0

6 I’m pretty sure. I did the work but it could always be wrong.

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Find the following integral

ololo11 [35]

There's nothing preventing us from computing one integral at a time:

$\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2$

$\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2$

$\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx$

Expand the integrand completely:

$x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x$

Then

$\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}$

4 0

2 years ago

If 14 g of a radioactive substance are present initially and 3 yr later only 7 g remain, how much of the substance will be pres

marishachu [46]

It would be 48 bc if you add it all up and subtract it and add again and multiply and divide and multiply within a and the substance of present after 6 yr you will see that i have wasted your time and that is not the answer

5 0

2 years ago

What is the result of 96 divided by 6? Use the model to find the answer.

gregori [183]

Answer:

the answer is 16

Step-by-step explanation:

i dont see any model but thats the result. (also so u don't waste points u can just use a calculator for things like this in the future)

3 0

2 years ago

Read 2 more answers

PLEASE HELP I NEED SOMEBODY TO PARAPHRASE THIS FOR ME! I'LL MARK BRAINLIEST!! 50 POINTS!!!