The [OH] of vinegar to the nearest hundredth is 2.82 * 10^-5
<h3>How to calculate the [OH] of a substance:</h3>
The sum of the pH and pOH of a substance is 14. Mathematically
[OH−] = Antilog (pOH)
Given the following parameters
[OH−] = Antilog (9.45)
Substitute
[OH−] = 2.82 * 10^-5
Hence the [OH] of vinegar to the nearest hundredth is 2.82 * 10^-5
Learn more on pH and pOH here:brainly.com/question/13557815
Probably a kite or an irregular trapezoid.
<span>Item Number of Liters Percentage of LemoneA 4 14%B x 8%Result 4+x 10%
For a mixture of solutions to form a resulting solution, we know
V1 * N1 + v2 * N2 = V * N
where, V1 = Volume of mixture of 1 N1 = Concentration of mixture 1V2 = Volume of mixture of 2 N2 = Concentration of mixture 2
V = volume of mixture N = Concentration of mixture
So solving we get:
(4+x)*10 = 4*14 + x * 8or, 10x-8x = 4*14-4*10or, 2x = 16or x = 8
so 8 litres of the solution B must be added to the solution<span>
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20 x 8.55= 171 that is what tracy was making per week.
8.55 + 1.30= 9.85 is her raise
20 x 9.85= 197 is how much she making with her new raise per week.
now to figure out how much MORE she is making go 197 - 171=$26 is your final answer
