All categories

3 years ago

Please sambady halp problem 5.

Mathematics

2 answers:

Fiesta28 [93]3 years ago

8 0

No because if Vicky has baseball practice every 10 days and starts on May 5th she would have practice on May 15th

lawyer [7]3 years ago

7 0

No because ten days from may 5th would be the 15th and then the next 10 days would be the 25

You might be interested in

FIND X Pleasee help mee

makkiz [27]

A. x= 6, -1. B. 1, -7

8 0

3 years ago

If the standard deviation of returns on the market is 20 percent, and the beta of a well-diversified portfolio is 1.5. Calculate

Luden [163]

Answer:

a. 30 percent.

Step-by-step explanation:

Given that:

The standard deviation of returns = 20 percent

Beta = 1.5

Beta=Standard deviation of portfolio × correlation/Standard deviation of market × Correlation

Since Correlation with the market will be +1;

Then;

The Standard deviation of portfolio = 1.5 × 20%

The Standard deviation of portfolio = 30.00%

3 0

3 years ago

Which graph represents this system? y=1/2x+3 y=3/2x-1

Zigmanuir [339]

It’s neither of the graphs that are showed in the photo

7 0

3 years ago

Ratio of cupcakes to muffins at a bakery is 6:5 the total is 99. how many cupcakes

sleet_krkn [62]

6+5 = 11

99/11 = 9

9x6 = 54

so 54 cupcakes

Hope this helps, and May the Force Be With You!

-Jabba

8 0

4 years ago

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

4 0

4 years ago