Question

varies inversely. suppose that when the current is 5 A, the resistance is 50 ohms. what is the resistance when the current is 2 A?

Answer 1

Current varies inversely with resistance :

         $\text { Current = } \dfrac{k}{\text {resistence}}$

When Current = 5A, resistance = 50 ohm

         $5 = \dfrac{k}{50}$

         $k = 5 \times 50$

         $k = 250$

So the equation is :

         $\boxed { \boxed {\text { Current = } \dfrac{250}{\text {resistence}} }}}$

When current = 2 A,

         $2A = \dfrac{250}{\text {resistence}}$

         $\text {resistence} = \dfrac{250}{2}$

         $\text {resistence} = 125$

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Answer: When current is 2A, resistence is 125 ohms.
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Answer 2

This law is known as Ohm's Law
$V=I*R$
where V is the voltage, I is the current, and R is the resistance
Science lesson aside, this is easy. In this case, voltage is constant.
First, if we multiply 5 A by 50 ohms, we get 250 V. That is our goal.
What can be multiplied by 2 to get to 250? 125. So the resistance is 125 ohms, given that the voltage is constant, and the current is 2 amperes