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3 years ago

Slove proportion 2/43 = j/13

Mathematics

1 answer:

I am Lyosha [343]3 years ago

5 0

Step-by-step explanation:

The easiest way to solve proportions is by cross multiplying.

2/43 = j/13

43j = 26

Now simply divide:

j = 26/43

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Joy is reading a 352-pagenovel forher summer reading prodject on monday she reads 3/8 of the novel on tuesday she reads 28 pages

schepotkina [342]

Answer:

104 Pages

Step-by-step explanation:

on Monday she reads 3/8 of the novel which means

x 352 = 132 pages

on Tuesday she reads 28 pages, doesn't require any calculations.

on Wednesday she reads 1/4 of the novel,

x 352 = 88

Just add all of that,

132+28+88=248 Pages

Subtract the novel pages by the read pages value

352-248=104pages.

PLEASE GIVE ME BRAINLYEST!!!!!!!!

3 0

3 years ago

Read 2 more answers

Please help and I will give brainliest if u do.

kirill115 [55]

Answer:

See explanation below

Step-by-step explanation:

The width is 4 inches

So, the area of the base is 20 inches squared

The height is 4 inches

So, the volume of the prism is 80 inches cubed

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3 years ago

Read 2 more answers

Prior Knowledge Questions (Do these BEFORE using the Gizmo.) Imagine you and your friends are making hot dogs. A complete hot do

slega [8]

Answer:

A. 8 complete hotdogs were made.

B. The wiener.

C. The bun.

Step-by-step explanation:

1 complete hotdog = 1 wiener + 1 bun

You have, 3*10 bun and 8 wiener

= 30 bun and 8 wiener

A. Since, we have 30 bun and 8 wiener and for 1 complete hotdog = 1 wiener + 1 bun

Therefore, 8 hotdogs = 8 wiener + 8 buns

= 8 complete hotdogs are made

Since 8 complete hotdogs are made, 8 wiener and 8 buns are used.

Therefore, the limiting ingredient is the wiener because it is the smallest number of ingredient and none of it was left after making the 8 hotdogs.

C. Since 8 complete hotdogs are made, 8 buns were used

So, the leftover buns = (30 - 8) buns

= 22 buns

The buns is the leftover ingredient

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3 years ago

X^2-8x+10=-4 quadratic equation written in standard form

ASHA 777 [7]

Rewriting the formula in standard form would be x^2-8x+14=0

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3 years ago

Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°

natima [27]

$\displaystyle\bf\\2cos^2y -sin\,y -1=0~~~for~~0^o\leq y \leq360^o\\\\cos^2y=1-sin^2y\\\\2(1-sin^2y) -sin\,y -1=0\\\\2-2sin^2y-sin\,y-1=0\\\\-2sin^2y-sin\,y+2-1=0\\\\-2sin^2y-sin\,y+1=0~~~\Big|\times(-1)\\\\2sin^2y+sin\,y-1=0$

$\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}$

5 0

3 years ago